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3 years ago

Now answer me that question because I will search them but I will not find them

Mathematics

2 answers:

sasho [114]3 years ago

7 0

Answer:

27: -5/11

28: 4x^2+12x

29: (2b-7c+5a)(2b-7c-5a)

30: 2/3

Step-by-step explanation:

27 is pretty simple, start by multiplying both sides by 6

so we have 2(6y+1)=y-3

this equal 12y+2=y-3

Subtract 1y and 2 from both sides to get

11y=-5

divide and get y= -5/11

28: this one is a lot to write so if you need me to explain it leave a comment but I got 4x^2+12x

29: Same deal as 28

(2b-7c+5a)(2b-7c-5a)

30: For this one I just distributed then combined like terms to get y=2/3

Aneli [31]3 years ago

3 0

Answer:

For which equations does the fraction 23 make the equation true? Select all that apply.

35 × □ = 20; I rewrote 35 as 351 and then multiplied 2 and 35 to get the numerator, and I multiplied 3 and 1 to get the denominator.

26 × □ = 18126; I rewrote 26 as 126 and then multiplied 1 and 2 to get the numerator, and I multiplied 3 and 26 to get the denominator.

48 × □ = 32; I rewrote 48 as 481 and then multiplied 2 and 48 to get the numerator, and I multiplied 3 and 1 to get the denominator.

22 × □ = 1423; I rewrote 22 as 221 and then multiplied 2 and 22 to get the numerator, and I multiplied 3 and 1 to get the denominator.

23 × □ = 15; I rewrote 23 as 123 and then multiplied 2 and 1 to get the numerator, and I multiplied 23 and 3 to get the denominator.

You might be interested in

Solve.write or draw to explain.

Alexandra [31]

Millie has a box of 100 cubes and a box of 70 cubes

she has 100+70 cubes together=170

She wants to make trains of 10 cubes each,

Which means,she needs to divide 170 with 10.

170/10

=17

she can make 17 trains of 10 cubes each..

4 0

4 years ago

1. The perimeter of a piece of paper is 18 cm.

OlgaM077 [116]

Answer:

a) length = 3 and width = 6

Area of the rectangle = 3 × 6 = 18 cm²

b) length = 7 and width = 2

Area of the rectangle = 7 × 2 = 14 cm²

c) length = 5 and width = 4

Area of the rectangle = 5× 4 = 20 cm²

Step-by-step explanation:

Step(i):-

Given perimeter of the paper = 18 cm

we know that the paper has a rectangle shape

The perimeter of the rectangle = 18 cm

2( l + w ) = 18

we choose length = 3 and width = 6

The perimeter of the rectangle = 2( 3+6) = 18 cm

Area of the rectangle = 3 × 6 = 18 cm²

we choose length = 7 and width = 2

The perimeter of the rectangle = 2( 7+2) = 18 cm

Area of the rectangle = 7 × 2 = 14 cm²

we choose length = 5 and width = 4

The perimeter of the rectangle = 2( 5+4) = 18 cm

Area of the rectangle = 5× 4 = 20 cm²

3 0

3 years ago

Simplify -(3xy^4)^-4

Umnica [9.8K]

Answer:

$\frac{-1}{81x^4y^16}$

Step-by-step explanation:

→Rewrite the expression so that the exponent is no longer negative. To do this, you write it as:

$\frac{-1}{(3xy^4)^4}$

→Apply the exponent (4) to the 3, x, and $y^4$ :

$\frac{-1}{81x^4y^16}$

7 0

3 years ago

5. What are the slope and y-intercept of the graph of y= 30 + 5?

BaLLatris [955]

Helloo 30 is the slope and 5 is the y-intercept ! hope this helps :)

5 0

2 years ago

Solution to the inequality 16x−33x<37x+27.

astra-53 [7]

The solution to the inequality is:

$x>\frac{-1}{2}$

Solution:

Given inequality is:

$16x-33x$

We have to find the solution to given inequality

$\mathrm{Add\:similar\:elements:}\:16x-33x=-17x$

$-17x$

$\mathrm{Subtract\:}37x\mathrm{\:from\:both\:sides}$

$-17x-37x$

Simplify the above inequality

$-54x$

$\mathrm{Multiply\:both\:sides\:by\:-1\:\left(reverse\:the\:inequality\right)}$

Remember that, change the inequality sign if you divide or multiply both sides by a negative number

If you divide or multiply both sides by a positive number,the inequality sign will not change

$\left(-54x\right)\left(-1\right)>27\left(-1\right)\\\\54x>-27$

$\mathrm{Divide\:both\:sides\:by\:}54$

$\frac{54x}{54}>\frac{-27}{54}\\\\x>-\frac{1}{2}$

Thus the solution to inequality is found

3 0

4 years ago

Now answer me that question because I will search them but I will not find them ​

Now answer me that question because I will search them but I will not find them