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Arlecino [84]
3 years ago
6

If one card is drawn from a standard deck of 52 cards, what is the probability of selecting one of the 4 aces

Mathematics
1 answer:
AlladinOne [14]3 years ago
5 0
The4 aces so probability = 4/52 = 1/13
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Anettt [7]
The answer to this problem is B
7 0
3 years ago
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The mr William two questions please!
melamori03 [73]

well, in short, the students and chaperones are at a 2 : 9 ratio, and we know there are 171 students, how many chaperones then, so long they maintain a 2:9 ratio?

\bf \cfrac{chaperones}{students}\qquad 2:9\qquad \cfrac{2}{9}\qquad \qquad \cfrac{x}{171}=\cfrac{2}{9}\implies 9x=2(171) \\\\\\ 9x=342\implies x=\cfrac{342}{9}\implies x=38

5 0
3 years ago
1) Order the animals by sleep time from least to greatest.
Zolol [24]
The way to line the animals is to put them in order going down. 0.433 56.3% 19/40 65.8%. Then you try to figure out what you need to convert so that you can get your answer. 56.3% changes to 0.563 because you move the decimal two places to the left. 65.8% changes to 0.658 and 19/40 is 0.475. 0.433 0.563 0.475 0.658. Now you compare each row to figure them out. When you do that your answer will be 0.433, 0.475, 0.563, and 0.658. I sleep about 9/24 of the day which is 0.375 and I will fit right befor 0.433.
4 0
3 years ago
Calculate the expected value, the variance, and the standard deviation of the given random variable X. (Round all answers to two
Tom [10]

Answer:

E (X) = 1.8

Var (X) = 0.36

σ = 0.6

Step-by-step explanation:

Solution:-

- Denote the random variable X : is the number of red marbles that Suzan has in her hand after she selects three marbles.

- Total sample space (bag) have the following quantity of colored marbles:

                Bag : { 3 Red , 2 Green }

- Suzan selects three marbles from the bag. The Event (X) defines the number of red marbles out of 3.

- The total number of outcomes / selections for randomly selecting 3 balls from the bag:

               All outcomes = 5 C 3 = 10

- The probability distribution of the random variable X, we will use combinations to determine the required probabilities:

  X = 1 red marble:

        P ( X = 1 ) : Suzan chooses 1 Red marble from the available 3 red marble and 2 green marbles.

        P ( X = 1 ) = [ 3C1*2C2 ] / all outcomes = (3*1) / 10 = 0.3

X = 2 red marble:

        P ( X = 2 ) : Suzan chooses 2 Red marble from the available 3 red marble and 1 green marbles.

        P ( X = 2 ) = [ 3C2*2C1 ] / all outcomes = (3*2) / 10 = 0.6

X = 3 red marble:

        P ( X = 3 ) : Suzan chooses 3 Red marble from the available 3 red marble.

        P ( X = 3 ) = [ 3C3] / all outcomes = (1) / 10 = 0.1

- The probability distribution is as follows:

          X :         1                 2                3

       P (X):       0.3            0.6              0.1

- The expected value E(X) for the given random variable X is:

                E ( X ) = ∑Xi*P(Xi)

                           = 1*0.3 + 2*0.6 + 3*0.1

                           =1.8

- The variance Var(X) for the given random variable X is:

                Var ( X ) = ∑Xi^2*P(Xi) - [ E(X) ] ^2

                               = 1^2*0.3 + 2^2*0.6 + 3^2*0.1 - 1.8^2

                               = 0.36

- The standard deviation for the given random variable X is:

                σ = √Var(X)

                σ = √0.36

                σ = 0.6

5 0
3 years ago
Multiply (5 + 3i)(5 − 3i) <br><br> 16 + 15i <br><br> 16 − 15i <br><br> 16 <br><br> 34
Annette [7]

Answer:

(5 + 3i)(5 − 3i) = 34

Step-by-step explanation:

The multiplication of two identical binomials who have different symbol, can be solved using the factoring case of a difference of squares:

(a-b).(a+b)=a^{2}-b^{2}

So, in this case:

(5+3i).(5-3i) = 5^{2}-(3i)^{2}

=25-9i^{2}

Remember that i=\sqrt{-1}

So: i^{2}=-1

We replace on the polynomial:

=25-9.(-1) = 25+9=34

3 0
3 years ago
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