3 years ago

If one card is drawn from a standard deck of 52 cards, what is the probability of selecting one of the 4 aces

Mathematics

1 answer:

AlladinOne [14]3 years ago

5 0

The4 aces so probability = 4/52 = 1/13

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Find the value of x and the value of y

steposvetlana [31]

Answer:

B. x = 7, y = 4√2

Step-by-step explanation:

Drop a vertical from the upper left corner

This creates a rectangle and a 45-45-90 triangle

The bottom of the rectangle is 3

The legs of the triangle are 4

Therefor

x = 4 + 3

x = 7

For a 45-45-90 triangle

the hypotenuse = leg * √2

y = 4√2

4 0

3 years ago

2x - y = 0<br> 4x - y = 0

Delicious77 [7]

Answer:

what's the question here ?

6 0

3 years ago

Read 2 more answers

(3x-4y)^2-(3x-4y)(3x+4y)

zheka24 [161]

Answer:

$-24xy + 32y^2$

Step-by-step explanation:

Hello!

We can use the special binomial product formulas:

$(a + b)^2 = a^2 + 2ab + b^2$
$(a + b)(a - b) = a^2 - b^2$

<h3>Simplify</h3>

$(3x - 4y)^2 - (3x - 4y)(3x + 4y)$
$(9x^2-24xy+16y^2) - (9x^2 - 16y^2)$
$9x^2 - 9x^2 - 24xy + 16y^2 + 16y^2$
$-24xy + 32y^2$

The simplified form is $-24xy + 32y^2$

6 0

2 years ago

Laney ordered 12 copies of the same book for his book club members the book cost $19 each in the order has a $15 shipping charge

liubo4ka [24]

Answer:

$408

Step-by-step explanation:

15+19=34

34×12=408

Total cost of order $408

7 0

3 years ago

One number is 7 more than another. The difference between their squares is 161. What are the numbers?

olga nikolaevna [1]

Let's say the numbers are "a" and "b"

now, we know one of them is 7 more than the other, so hmmm let's say "b" is 7 more than "a", so b = a + 7

the difference of their squares is 161, alrite

$\bf a^2-b^2=161\qquad b=a+7\implies a^2-(a+7)^2=161
\\\\\\
a^2-(a^2+14a+49)=161\implies \underline{a^2-a^2}-14a-49=161
\\\\\\
-14a-49=161\implies -49-161=14a\implies -210=14a
\\\\\\
\cfrac{-210}{14}=a$

and surey you know how much that is

now, what's "b"? well, b = a + 7

3 0

3 years ago