Help meee yall pleaseeeee

Each angle of an equiangular triangle is what degree angle

Alexandra [31]

An equiangular triangle adds up to 180 so divide that by 3, which is the number of sides, and you get, 60, therefore, each side is 60<span>° angle.</span>

5 0

2 years ago

Carlos drew a plan for his garden on a coordinate plane. Rose bushes are located at A(–5, 4), B(3, 4), and C(3, –5)

BartSMP [9]

Given:

A(-5,4)

B(3,4)

C(3,-5)

So point D is:

so point D is (-5,-5)

For AB is

Distance between two point is:

$\begin{gathered} (x_1,y_1)and(x_2,y_2) \\ D=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2} \end{gathered}$

so distance between A(-5,4) and B(3,4) is:

$\begin{gathered} D=\sqrt[]{(3-(-5))^2+(4-4)^2} \\ =\sqrt[]{(8)^2+0^2} \\ =8 \end{gathered}$

So AB is 8 unit apart.

For B(3,4) and C(3,-5).

$\begin{gathered} D=\sqrt[]{(3-3)^2+(-5-4)^2} \\ =\sqrt[]{0^2+(-9)^2} \\ =9 \end{gathered}$

So BC is 9 unit apart.

For fourth bush point is (-5,-5) it left of point C(3,-5) is:

$\begin{gathered} D=\sqrt[]{(3-(-5))^2+(-5-(-5))^2} \\ =\sqrt[]{(8)^2+0^2} \\ =8 \end{gathered}$

so fourth bush is 8 unit left of C.

For fourth bush(-5,-5) below to point A(-5,4)

$\begin{gathered} D=\sqrt[]{(-5-(-5))^2+(4-(-5))^2} \\ =\sqrt[]{0^2+9^2} \\ =9 \end{gathered}$

so fourth bush 9 units below of A.

8 0

9 months ago

Phoebe usually drives to work each day on a 12-mile road that is currently closed for construction. While the road is closed she

Mumz [18]

The total distance phoebe has to drive each day (round trip) while her usual route is closed is 42 miles

<h3>What is a Pythagoras theorem?</h3>

The square of the longest side is equal to the square of the sum of the othersides.

Before we can calculate the total distance, we will need to get the hypotenuse on both sides using the Pythagoras theorem as shown:

H^2= 12^2 + 9^2

H² = 144 + 81

H² = 225

H = 15

For the other hypotenuse

h² = 12² + 5²

h² = 144 + 25

h² = 169

h = 13 mils

The total distance = 5 + 15 + 9 + 13

The total distance = 42 miles

The total distance phoebe has to drive each day (round trip) while her usual route is closed is 42 miles

Learn more on Pythagoras theorem here: brainly.com/question/12306722

3 0

1 year ago

A certain population of mice is growing exponentially. After one month there are 48. After 2 months there are "192" mice. Write

REY [17]

Answer:

P(t) = 12e^1.3863k

Step-by-step explanation:

The general exponential equation is represented as;

P(t) = P0e^kt

P(t) is the population of the mice after t years

k is the constant

P0 is the initial population of the mice

t is the time in months

If after one month there are 48 population, then;

P(1) = P0e^k(1)

48 = P0e^k ...... 1

Also if after 2 months there are "192" mice, then;

192 = P0e^2k.... 2

Divide equation 2 by 1;

192/48 = P0e^2k/P0e^k

4 = e^2k-k

4 = e^k

Apply ln to both sides

ln4 = lne^k

k = ln4

k = 1.3863

Substitute e^k into equation 1 to get P0

From 1, 48 = P0e^k

48 = 4P0

P0 = 48/4

P0 = 12

Get the required equation by substituting k = 1.3863 and P0 = 12 into equation 1, we have;

P(t) = 12e^1.3863k

This gives the equation representing the scenario

8 0

2 years ago

An equivalent expression for n x a using only addition

Rina8888 [55]

<u /><u /><u /> $n\times a\quad =\quad (a+a+a+a+a+.....+a)$

6 0

3 years ago

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