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Nataly [62]
3 years ago
13

The floor of my dining room is 14 ft by 16 ft. If I want to tile the floor with 1 square tiles, how many tiles will I need for t

he room?
Mathematics
2 answers:
marissa [1.9K]3 years ago
7 0

Answer:

224

Step-by-step explanation:

times 16x14

serg [7]3 years ago
6 0

Answer:

16x 14 =224

1x224=224

There your answer.

Step-by-step explanation:

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How do you solve this equation log(3x+1)=5
Len [333]

log_{10} 3x+1=5

3x+1=10^5

3x+1=100000

3x=99999

x=333333


Just remember that in the form of log_ab=x, you get a^x=b.


7 0
3 years ago
Read 2 more answers
System of conics help
ZanzabumX [31]

Answer:

Solutions are (6,3) and (-2,3).

Step-by-step explanation:

From the first equation given we can write:

(x-2)^{2} = 16-(y-3)^{2}\\  

substituting for (x-2)^{2} in the second equation given we get

\frac{16-(y-3)^{2}}{16} + \frac{(y-3)^{2}}{64} = 1

\frac{-(y-3)^{2}}{16} + \frac{(y-3)^{2}}{64} =0

∴ y=3

Putting y=3 in the first equation we get

(x-2)^{2} = 16

x-2 = ±4

Hence x=6 or x=-2.

7 0
3 years ago
What is the area of the obtuse triangle given below?
Alex

Answer:

64 sq. units

Step-by-step explanation:

A = \frac{hb}{2}

A = \frac{16*8}{2} = 64 sq. units

5 0
3 years ago
A company that produces fine crystal knows from experience that 13% of its goblets have cosmetic flaws and must be classified as
Kisachek [45]

Answer:

(a) The probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b) The probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c) The probability that at most five must be selected to find four that are not seconds is 0.9453.

Step-by-step explanation:

Let <em>X</em> = number of seconds in the batch.

The probability of the random variable <em>X</em> is, <em>p</em> = 0.31.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X</em> is:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...

(a)

Compute the probability that only one goblet is a second among six randomly selected goblets as follows:

P(X=1)={6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=6\times 0.13\times 0.4984\\=0.3888

Thus, the probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b)

Compute the probability that at least two goblet is a second among six randomly selected goblets as follows:

P (X ≥ 2) = 1 - P (X < 2)

              =1-{6\choose 0}0.13^{0}(1-0.13)^{6-0}-{6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=1-0.4336+0.3888\\=0.1776

Thus, the probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c)

If goblets are examined one by one then to find four that are not seconds we need to select either 4 goblets that are not seconds or 5 goblets including only 1 second.

P (4 not seconds) = P (X = 0; n = 4) + P (X = 1; n = 5)

                            ={4\choose 0}0.13^{0}(1-0.13)^{4-0}+{5\choose 1}0.13^{1}(1-0.13)^{5-1}\\=0.5729+0.3724\\=0.9453

Thus, the probability that at most five must be selected to find four that are not seconds is 0.9453.

8 0
3 years ago
I dont understand the circled question ....please help!
irina1246 [14]

Parallel lines NEVER intersect/meet, this is because they have the same slope and they go in the same direction.

These lines are parallel because they have the same slopes of 3/4 (because they go 3 units up and 4 units to the right. slope = rise/run)

7 0
3 years ago
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