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3 years ago

Find the length of RA. A. 42 B. 84 C. 14 D. 7

Mathematics

2 answers:

uranmaximum [27]3 years ago

8 0

Answer:

B) 84

Step-by-step explanation:

ΔLRU ≅ ΔLAU {SAS congruent}

Therefore, UA = UR {CPCT}

6m = 3m +21

Subtract 3m from both sides

6m - 3m = 3m + 21 -3m

3m = 21

Divide both sides by 3

3m/3 = 21/3

m = 7

RA = RU + UA

= 3m + 21 + 6m {add like terms}

= 9m + 21 {Plug in m =7}

= 9*7 + 21

= 63 + 21

RA = 84 units

fiasKO [112]3 years ago

3 0

Answer:

$\large \boxed{\mathrm{B. \ 84}}$

Step-by-step explanation:

$LU$ bisects $RU$ and $UA$ .

$RU=UA$

$3m+21=6m$

Solve for m.

Subtract 3m from both sides.

$21=3m$

Divide both sides by 3.

$7=m$

Calculate $RA$ .

$RA=3m+21+6m$

$RA=9m+21$

Put m = 7.

$RA=9(7)+21$

$RA=63+21$

$RA=84$

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I am stuck on this question of my maths test.

V125BC [204]

Answer:

angle y

58 + 38 + y = 180 (angle sum property)

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y = 84

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x = 29 (58/2)

(angle subtended by an arc at centre is double the arc at any point on remaining part of centre)

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2 years ago

Given cos A= 3 ― 10 and tan A <0, find sin A.

QveST [7]

First we are going to start by subtracting 3-10 and that gives us 7 so then you divide 7 by 4”3 and you get 2.3

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1 year ago

14. Find mMK please :)

MrRissso [65]

Answer:

Step-by-step explanation:

11) strategy: since they tell us. indirectly, that the length of JK is the same as LM then we can set those two equal, solve for X and then.. when we have X we can figure out the lenght of JK and LM and then just divide that by 2 go get PK ( :0 Player Killer ??? no , not that PK)

solve JK and LM

3x + 23 =9x-19

42 = 6x

7 = x

now that we know x = 7 plug it into either equation to come up with the length of JK or LM . I'll pick JK just b/c it was 1st

3(7) + 23 = JK

21+23 = JK

44 = JK

now take half of 1/2*JK= 22 that is PK ( are you sure that 's not player killer?)

PK = 22

12) strategy: set the two arcs BG and GC equal and solve for X, then plug x into either equation and the multiply the answer by 2 to find arc AB

9x-20 = 5x + 28

4x = 48

X = 12

9(12) -20 = BG

88 = BG

2*88 + AB

176 = AB

13) done

14) strategy: find the angle at L, and that will also be the arc of MK

copy and past the below helpful trig functions into your computer

Use SOH CAH TOA to recall how the trig functions fit on a triangle

SOH: Sin(Ф)= Opp / Hyp

CAH: Cos(Ф)= Adj / Hyp

TOA: Tan(Ф) = Opp / Adj

copy and past the above :

use which ever trig function you want , we have all the sides of the triangle, I'll use CAH

Cos(Ф) = 9/15

Ф = arcCos(9/15)

Ф = 53.13010°

arc MK = 53.13010°

15) strategy: arc JK is just 2 times MK

2*MK = 106.26020°

arc MK = 106.26020°

16) find arc JPK strategy: JPK is just the remaining part of a full circle of 360 - MK = 253.7397°

arc JPK = 253.7397°

7 0

2 years ago

What are the roots of the quadratic equation below? x2 + 2x= -5

muminat

Answer:

No real root.

Complex roots:

$x = -1 \pm 2i$

Step-by-step explanation:

$x^2 + 2x = -5$

$x^2 + 2x + 5 = 0$

There are no two integers whose product is 5 and whose sum is 2, so this trinomial is not factorable. We can use the quadratic formula.

$x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

$x = \dfrac{-2 \pm \sqrt{2^2 - 4(1)(5)}}{2(1)}$

$x = \dfrac{-2 \pm \sqrt{4 - 20}}{2}$

$x = \dfrac{-2 \pm \sqrt{-16}}{2}$

Since we have a square root of a negative number, there are no real roots. If you have learned complex numbers, then we can continue.

$x = \dfrac{-2 \pm 4i}{2}$

$x = -1 \pm 2i$

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Korolek [52]

The area is 24

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Hope this helped. Have a great day!

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2 years ago

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