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Korvikt [17]
3 years ago
13

Find the length of RA. A. 42 B. 84 C. 14 D. 7

Mathematics
2 answers:
uranmaximum [27]3 years ago
8 0

Answer:

B) 84

Step-by-step explanation:

ΔLRU ≅ ΔLAU   {SAS congruent}

Therefore, UA = UR    {CPCT}

 6m = 3m +21

Subtract 3m from both sides

6m - 3m = 3m + 21 -3m

        3m = 21

Divide both sides by 3

    3m/3 = 21/3

m = 7

RA = RU + UA

    = 3m + 21 + 6m {add like terms}

    = 9m + 21   {Plug in m =7}

    = 9*7 + 21

    = 63 + 21

RA = 84 units

fiasKO [112]3 years ago
3 0

Answer:

\large \boxed{\mathrm{B. \ 84}}

Step-by-step explanation:

LU bisects RU and UA.

RU=UA

3m+21=6m

Solve for m.

Subtract 3m from both sides.

21=3m

Divide both sides by 3.

7=m

Calculate RA.

RA=3m+21+6m

RA=9m+21

Put m = 7.

RA=9(7)+21

RA=63+21

RA=84

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If x varies directly with y and x = 3.5 when y = 14, find x when y = 18.
maks197457 [2]

Answer:

x = 4.5

Step-by-step explanation:

there's definitely other ways to solve this, but I used a proportion.

\frac{3.5}{x} = \frac{14}{18}

Then you can make this equation:

14x = 3.5 * 18

I solved for it and got 4.5 .

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Complete the table for y=1/2x-3
Readme [11.4K]

Tables are created by substitute a set of input values into the function to create outputs. The required table is as shown below

<em>x | y</em>

<em>0   -3 </em>

<em>1   -2.5</em>

<em>2   -2 </em>

<h3>Tables and values</h3>

Tables are created by substitute a set of input values into the function to create outputs

Using x = 0, 1 and 2 as the input values

Given the function

y = 1/2x - 3

If x = 0

y = 1/2(0) - 3

y = -3

If x = 1

y = 1/2(1) - 3

y = -2.5

If x = 2

y = 1/2(2) - 3

y = -2

Hence the required table is as shown below

x | y

0   -3

1   -2.5

2   -2

Learn more on tables and values here: brainly.com/question/12151322

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8 0
1 year ago
Because not all airline passengers show up for their reserved seat, an airline sells 125 tickets for a flight that holds only 12
melamori03 [73]

Answer:

98.75% probability that every passenger who shows up can take the flight

Step-by-step explanation:

For each passenger who show up, there are only two possible outcomes. Either they can take the flight, or they do not. The probability of a passenger taking the flight is independent from other passenger. So the binomial probability distribution is used to solve this question.

However, we are working with a large sample. So i am going to aproximate this binomial distribution to the normal.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

The probability that a passenger does not show up is 0.10:

This means that the probability of showing up is 1-0.1 = 0.9. So p = 0.9

Because not all airline passengers show up for their reserved seat, an airline sells 125 tickets

This means that n = 125

Using the approximation:

\mu = E(X) = np = 125*0.9 = 112.5

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{125*0.9*0.1} = 3.354

(a) What is the probability that every passenger who shows up can take the flight

This is P(X \leq 120), so this is the pvalue of Z when X = 120.

Z = \frac{X - \mu}{\sigma}

Z = \frac{120 - 112.5}{3.354}

Z = 2.24

Z = 2.24 has a pvalue of 0.9875

98.75% probability that every passenger who shows up can take the flight

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3 years ago
10,885 divided by 1,555
Nikolay [14]
Yes? 10,885/1,555 is 7
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2 years ago
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