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Aleonysh [2.5K]
2 years ago
14

10,885 divided by 1,555

Mathematics
1 answer:
Nikolay [14]2 years ago
7 0
Yes? 10,885/1,555 is 7
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Please someone help me out
hichkok12 [17]

Answer:

Hopefully you can see the image.

Basically what's going on is the shape is being reflected over this line (x = -1) rather than the origin line.

Hope this helps :)

3 0
3 years ago
What relation is a graph that is just a straight horizontal line, no slope or anything.
zubka84 [21]

Answer: 0, Zero

Step-by-step explanation: all horizontal lines are of the form "y = some number", and the equation "y = some number" always graphs as a horizontal line.

5 0
3 years ago
In order to answer the question correctly, please use the image below:
Maurinko [17]

Answer:

240

Step-by-step explanation:

m xyz 2(120)

(sorry about the explaination)

5 0
2 years ago
Read 2 more answers
20) Use the distributive property to factor the expression. 10xz − 20yz
Paraphin [41]

Answer:

C. 10z(x - 2y)

Step-by-step explanation:

10xz − 20y

Factor the terms

Factors of   10xz =          2 ×      5 × x ×        z

Factors of -20yz = (-1) × 2 × 2 × 5 ×       y × z

Identify their greatest common  factor

The common factors are 2, 5, and z. The greatest common  factor is 10z.

Rewrite them with the GCF as a factor

 10xz = 10z ×      x

-20yz = 10z × (-2y)

Replace the terms in the original expression with the factored terms

10xz − 20yz = 10z(x) + 10z(-2y)

Use the distributive property to isolate the greatest common factor

10z(x) + 10z(-2y) = 10z(x - 2y)

3 0
3 years ago
Pada hari kantin sebanyak 800 naskah kupon telah dijual,harga senaskah kupon masing masing rm 30 dan rm 50 .jumlah wang diperole
solniwko [45]

Answer:

Step-by-step explanation:

On the day of the canteen, 800 coupons were sold, the price of each coupon was RM 30 and RM 50 respectively. The amount of money earned from the sale of coupons was RM30000. How many copies of RM30 and RM50 coupons were sold?

Let:

RM 30 = x

RM 50 = y

x + y = 800 - - - (1)

30x + 50y = 30000 - - - (2)

From (1)

x = 800 - y

Put x = 800 - y in (2)

30(800 - y) + 50y = 30000

24000 - 30y + 50y = 30000

24000 + 20y = 30000

20y = 30000 - 24000

20y = 6000

y =

4 0
2 years ago
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