If you are trying to figure out the distance between the top of the tree and the end of the shadow, use a^2 + b^2 = c^2 where c is the hypotenuse and a and b are the legs of the right triangle.
5^2 + 4^2 = c^2
25 + 16 = c^2
41 = c^2
c = √41 = 6.4 meters
Answer:
Step-by-step explanation:
this goes with BODMAS .so it means bracket of divison,multiplication ,addition and subtraction
this means that you would have to solve the one in the bracket first before you'll continue with the rest,that is the subtraction.
Answer:
10 players
Step-by-step explanation:
so a percentage is really just like a fraction or decimal so were going to turn it into a decimal by moving the decimal point two places to the left making it .20 then to figure out the answer we're going to multiply 50 by .20 to get 10
Part A. You have the correct first and second derivative.
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Part B. You'll need to be more specific. What I would do is show how the quantity (-2x+1)^4 is always nonnegative. This is because x^4 = (x^2)^2 is always nonnegative. So (-2x+1)^4 >= 0. The coefficient -10a is either positive or negative depending on the value of 'a'. If a > 0, then -10a is negative. Making h ' (x) negative. So in this case, h(x) is monotonically decreasing always. On the flip side, if a < 0, then h ' (x) is monotonically increasing as h ' (x) is positive.
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Part C. What this is saying is basically "if we change 'a' and/or 'b', then the extrema will NOT change". So is that the case? Let's find out
To find the relative extrema, aka local extrema, we plug in h ' (x) = 0
h ' (x) = -10a(-2x+1)^4
0 = -10a(-2x+1)^4
so either
-10a = 0 or (-2x+1)^4 = 0
The first part is all we care about. Solving for 'a' gets us a = 0.
But there's a problem. It's clearly stated that 'a' is nonzero. So in any other case, the value of 'a' doesn't lead to altering the path in terms of finding the extrema. We'll focus on solving (-2x+1)^4 = 0 for x. Also, the parameter b is nowhere to be found in h ' (x) so that's out as well.
