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Ronch [10]
3 years ago
11

50 POINTS! What is the value of arcsin(−1/2) in degrees?

Mathematics
2 answers:
Veronika [31]3 years ago
4 0

Answer:

-\frac{\pi }{6}

Step-by-step explanation:

arcsin(−1/2) = -arcsin(1/2)

In the table of common values,

-arcsin of 1/2 = π/6 = -π/6

Note: Memorize the results of the common values.

Stella [2.4K]3 years ago
3 0

Answer: 330°

Step-by-step explanation:

arcsin means sin^-1

So, arcsin(−1/2) is sin^-1(−1/2).

Now,

Let y = sin^-1(−1/2)

y = -30°

If range is between 0° and 360° then,

y = 360° - 30°

y = 330°

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Deana bought 12 packages of batteries. Some of the packages contained 4 batteries and some contained 6 batteries. She bought a t
NARA [144]

Answer:

She bought 7 battery packs containing 6 batteries

Step-by-step explanation:

4bx5= 20 batteries

6bx7=42 batteries

42+20=62

7 0
3 years ago
Calculate 41% 0f 51kg
vlabodo [156]
20.91

51 x 0.41 = 20.91
5 0
3 years ago
Read 2 more answers
What is 10t =90 and how do I solve this?please help
Nesterboy [21]
To solve this you have to divide 90 by 10 which would be 9 so


t=9

Hope it helps
6 0
4 years ago
Island A is 160 miles from island B. A ship captain travels 220 miles from island A and then finds that he is off course and 200
Angelina_Jolie [31]

Answer:

=135.53°

Step-by-step explanation:

The bearing that the captain should turn is the angle difference between the two islands from the position of the ship.

Let C be the position of the ship, then

AB is c=160

AC is b=220

BC is a=200

We use the cosine rule as follows:

c²=a²+b²-2ab Cos C

160²=200²+220²-2×200×220 Cos C

25600=88400-88000Cos C

88000 Cos C=88400-25600

88000Cos C=62800

Divide both sides by 88000.

Cos C=62800/88000

=0.7136

C=44.47°

He should turn (180°-44.47°)=135.53°

3 0
3 years ago
If two objects travel through space along two different curves, it’s often important to know whether they will collide. (Will a
galina1969 [7]

Answer:

<em>Both objects collide at t=3 in the point  <9,9,9></em>

Step-by-step explanation:

<em>Collision Of Moving Objects </em>

Two objects can describe different trajectories in the space. Those trajectories can intersect in one or more points but it doesn't mean they collide. Collision occurs if they are in the same position at the same time. If we know the positions as a function of time of each object, we could try so find if, for a given time, they are in the same position.

The positions of two object are given as

r1(t)=

r2(t)=

Let's find out if there is at least one value of t that makes both positions to be the same. We can try by equating one of the three coordinates and testing if the value of t make both have the same x,y,z coordinate. Let's try equating the x-components of both

t^2=4t-3

Rearranging

t^2-4t+3=0

Factoring

(t-1)(t-3)=0

We found two solutions

t=1,\ t=3

for t=1 the x-coordinates are

x1=t^2=1

x2=4t-3=1

For t=3

x1=t^2=9

x2=4t-3=9

Now we'll test both values in the y-coordinates

y1=7t-12

y2=t^2

For t=1

y1=-5

y2=1

Thus they don't collide at t=1. Let's try t=3

y1=7(3)-12=9

y2=3^2=9

Now let's try the z-coordinate for t=3

z1=t^2=9

z2=5t-6=9

Since the three coordinates match, we can say both objects collide at t=3 in the point  <9,9,9>

6 0
3 years ago
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