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Aleksandr-060686 [28]
3 years ago
10

What is (766*67*89*8*9*87656*7*908786*5*687*78*87*797*87897*8989*089*7654*4*367567*98097987567544*535*567*9*8*6787)0(5*64543534*

243467*5*9*7675*643*23*65*878778776546453*53*467*798*89*675*546*32*53*6465*8*76546*34)
Mathematics
2 answers:
romanna [79]3 years ago
4 0

Answer:

0 What is (766*67*89*8*9*87656*7*908786*5*687*78*87*797*87897*8989*089*7654*4*367567*98097987567544*535*567*9*8*6787)0(5*64543534*243467*5*9*7675*643*23*65*878778776546453*53*467*798*89*675*546*32*53*6465*8*76546*34)

Step-by-step explanation:

kodGreya [7K]3 years ago
3 0

Answer:

The answer is 0

Step-by-step explanation:

You might be interested in
Some scientists believe alcoholism is linked to social isolation. One measure of social isolation is marital status. A study of
alexandr402 [8]

Answer:

1) H0: There is significant evidence of independence between marital status and diagnostic

H1: There is significant evidence of an association between marital status and diagnostic

2) The statistic to check the hypothesis is given by:

\chi^2 =\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}

3) \chi^2 = \frac{(21-33.143)^2}{31.143}+\frac{(37-41.429)^2}{41.429}+\frac{(58-41.429)^2}{41.429}+\frac{(59-46.857)^2}{46.857}+\frac{(63-58.571)^2}{58.571}+\frac{(42-58.571)^2}{58.571} =19.72

4) p_v = P(\chi^2_{2} >19.72)=0.00005222

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(19.72,2,TRUE)"

Since the p values is lower than the significance level we have enough evidence to reject the null hypothesis at 5% of significance, and we can say that we have associated between the two variables analyzed.

Step-by-step explanation:

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Assume the following dataset:

                    Alcoholic    Undiagnosed Alcoholic     Not Alcoholic   Total

Married             21                         37                               58                  116

Not Married      59                        63                               42                  164

Total                  80                        100                             100                 280

Part 1

We need to conduct a chi square test in order to check the following hypothesis:

H0: There is significant evidence of independence between marital status and diagnostic

H1: There is significant evidence of an association between marital status and diagnostic

The level os significance assumed for this case is \alpha=0.05

Part 2

The statistic to check the hypothesis is given by:

\chi^2 =\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}

The table given represent the observed values, we just need to calculate the expected values with the following formula E_i = \frac{total col * total row}{grand total}

And the calculations are given by:

E_{1} =\frac{80*116}{280}=33.143

E_{2} =\frac{100*116}{280}=41.429

E_{3} =\frac{100*116}{280}=41.429

E_{4} =\frac{80*164}{280}=46.857

E_{5} =\frac{100*164}{280}=58.571

E_{6} =\frac{100*164}{280}=58.571

And the expected values are given by:

                    Alcoholic    Undiagnosed Alcoholic     Not Alcoholic   Total

Married         33.143                    41.429                        41.429              116

Not Married  46.857                   58.571                        58.571              164

Total                  80                        100                             100                 280

Part 3

And now we can calculate the statistic:

\chi^2 = \frac{(21-33.143)^2}{31.143}+\frac{(37-41.429)^2}{41.429}+\frac{(58-41.429)^2}{41.429}+\frac{(59-46.857)^2}{46.857}+\frac{(63-58.571)^2}{58.571}+\frac{(42-58.571)^2}{58.571} =19.72

Part 4

Now we can calculate the degrees of freedom for the statistic given by:

df=(rows-1)(cols-1)=(2-1)(3-1)=2

And we can calculate the p value given by:

p_v = P(\chi^2_{2} >19.72)=0.00005222

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(19.72,2,TRUE)"

Since the p values is lower than the significance level we have enough evidence to reject the null hypothesis at 5% of significance, and we can say that we have associated between the two variables analyzed.

8 0
3 years ago
What is y=3(2x+1)+5<br><br> work need to be shown
jonny [76]

Answer:

In slope intercept form, this equation is y = 6x + 8

Step-by-step explanation:

All you need to do to get this to slope intercept form is to distribute the term and then combine like terms.

y = 3(2x + 1) + 5 ----> Distribute

y = 6x + 3 + 5 ----> Combine like terms

y = 6x + 8

6 0
3 years ago
Points! have a nice day
deff fn [24]

The answer is thanks a lot

4 0
3 years ago
Read 2 more answers
I'm learning about Equivalent systems of equations, please help!
kobusy [5.1K]
OK to solve this, we have to solve each system presented through elimination or substitution and find which one is equivalent to that of the teacher's!

First let's solve for the teacher's:
-2x+5y=10
-3x+9y=6
Solve by substitution (I think elimination might be easier to do for this one, but I don't really remember 100% sorry!)
Isolate the x (or y) variable in the first equation
-2x+5y=10
-2x=10-5y
x= \frac{10-5y}{-2}
Substitute x into the next equation and solve for y
-3(10-5y/2)+9y=6
3*10-5y/2+9y=6
(multiply both sides by 2)
3(10-5y)+18y=12
30-15y+18y=12
30+3y=12
3y=-18
y=-6

Substitute in x
x= -10-5(-6)/2
x=-20

TEACHER'S ANSWER (-20,-6)


GOKU
x-3y=-2
-2x+5y=-7
Do the same as above
Solve for x
x-3y=-2
x=3y-2
Plug in
-2(3y-2)+5y=-7
4-6y+5y=-7
4-y=-7
-y=-11
y=11

x=(3(11)-2)
x=31
GOKU'S ANSWER (31, 11)

SELINA:
-5x+14y=16
-3x+9y=12
One last time!! :)

-5x+14y=16
-5x=16-14y
x=(16-14y)/-5

-3(-(16-14y/5)+9y=12
3*16-14y/5+9y=12
3*16-14y+45y=60 
48-42y+45y=60
48+3y=60
3y=12
y=4

x=-(16-14(4))/5
x=8
SELINA'S ANSWER
(8,4)

So neither Goku or Selina got the same answer as the teacher
3 0
3 years ago
Read 2 more answers
Jamie is hiking up a small mountain. He climbs up at a constant rate of 300 feet/hour until he reaches the peak at 1,500 feet. A
aleksandr82 [10.1K]

Answer:

a. d = 1500 - 300t. b. after 2 hours and after 4 hours

Step-by-step explanation:

a. Since Jamie hikes up the mountain at a rate of 300 ft/hr, and the mountain is 1500 ft high, his distance, d from the peak of the mountain at any given time,t  is given by

d = 1500 - 300t.

b.If Jamie distance d = 900 ft, then the equation becomes,

900 = 1500 - 300t

900 - 1500 = -300t

-600 = -300t

t = -600/-300

t = 2 hours

The equation d = 1500 - 300t. also models his distance from the peak of the  mountain if he hikes down at a constant rate of 300 ft/hr

At d = 900 ft, the equation becomes

900 = 1500 - 300t

900 - 1500 = -300t

-600 = -300t

t = -600/-300

t = 2 hours

So, on his hike down the mountain, it takes him another 2 hours to be 900 ft from the peak of the mountain.

So, he is at 900 ft on his hike down after his start of hiking up the mountain at time t = (2 + 2) hours = 4 hours. Since it takes 2 hours to climb to the peak of he mountain and another 2 hours to climb down 900 ft from the peak of the mountain.

4 0
3 years ago
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