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julsineya [31]
3 years ago
14

PLEASE HELP TIMED

Mathematics
1 answer:
Lerok [7]3 years ago
7 0
Answer: C) (9x^4-x^3-x)/5
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Given that the hypotenuse of this right triangle is 25 cm long and that tan(Θ) = 3 Find the values of x and y, accurate to the n
saveliy_v [14]
The wording of this problem indicates that there was an illustration.  Could you possibly share that illustration?

Working without an illustration:

If tan theta = 3, then tan theta = opp/adj = 3/1.  This tells us that the opp side is 3 times as long as is the adj. side.  Let x be the shorter side, i. e., let x represent the adjacent side; then y is the longer side and represents the opposite side.

Then y = 3x (the opp side is 3x the adj side in length).

Applying the Pyth. Thm.    a^2 + b^2 = c^2,

x^2 + (3x)^2 = hyp^2 = (25 cm.)^2

So x^2 + 9x^2 = (625 cm^2)

10x^2 = 625 cm^2, or x^2 = (625 cm^2) / 10 = 62.5 cm^2

x = 7.91 cm.  Therefore, y = 3(7.91) = 23.72 cm.

We were supposed to round off these answers to the nearest 10th cm.
Therefore, x = 7.9 cm and y = 23.7 cm

Would that be A, B, C or D?
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3 years ago
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Finding values or<br> k(x) = x - 2<br> h(x) = x2 +1<br> (h + k)(2) =
Serjik [45]

Answer:

<h2>(h + k)(2) = 5</h2>

Step-by-step explanation:

(h+k)(x)=h(x)+k(x)\\\\\bold{METHOD\ 1:}\\\\k(x)=x-2,\ h(x)=x^2+1\\\\(k+h)(2)=h(2)+k(2)\\\\\text{Calculate}\ h(2)\ \text{and}\ k(2).\\\text{Put}\ x=2\ \text{to the equations of the functions}\\\\h(2)=2^2+1=4+1=5\\k(2)=2-2=0\\\\\text\\\\\text{Substitute:}\\\\(h+k)(2)=5+0=5

\bold{METHOD\ 2:}\\\\k(x)=x-2,\ h(x)=x^2+1\\\\(h+k)(x)=h(x)+k(x)=(x^2+1)+(x-2)=x^2+x-1\\\\(h+k)(2)-\text{put}\ x=2\\\\(h+k)(2)=2^2+2-1=4+2-1=6-1=5

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Step-by-step explanation:

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