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Basile [38]
3 years ago
10

9.

Mathematics
1 answer:
myrzilka [38]3 years ago
5 0
Using <span>Compound interest formula:
</span>
<span><span>The exponential function for calculating the amount of money after <span>t <span>years, <span>A<span>(<span>t<span>), where<span> P <span>is the initial amount or principal, the annual interest rate is <span>r <span>and the number of times<span> interest is compounded per year is <span>n, is given by</span>
</span></span></span></span></span></span></span></span></span></span></span></span>A(t) = p(1+ \frac{r}{n} )^{nt}

</span><span>from the given information:
p = 1,380 , r = 0.05 , t =3  and </span><span>compounded daily ⇒⇒⇒ n =365

Amount after 3 years = </span>
<span>A(t) = 1380(1+ \frac{0.05}{365} )^{365*3} = 1,603.315


</span>


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Is this set of ordered pairs<br> a function?<br> (2,6), (4,9) (-2,6), (14, 11)
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If the following system of equations was written as a matrix equation in the form AX = C, and matrix A was expressed in the form
IrinaVladis [17]

Answer: a-b+c+d =4


Step-by-step explanation:

The given system of equation is

2x+8y=7\\4x-2y=9

from this we have the following matrices

A_1 =\begin{bmatrix}\\2 &8 \\ \\4&2 \\\end{bmatrix}\ ,X=\begin{bmatrix}\\x\\ \\y\\\end{bmatrix}\text{and}\ C=\begin{bmatrix}\\7\\ \\9\\\end{bmatrix}

the given matrix A =\begin{bmatrix}\\a &c \\ \\b &d \\\end{bmatrix}

On comparing Matrix  A_1 with Matrix A

\begin{bmatrix}\\a &c \\ \\b &d \\\end{bmatrix}=\begin{bmatrix}\\2&8 \\ \\4 &-2 \\\end{bmatrix}

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Can someone answer this? Thanks :)
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Answer:

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Step-by-step explanation:

Draw out the picture and use the Pythagorean theorem (equation is written in blue) to solve.

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4 0
3 years ago
If you roll two fair dice repeatedly, what is the probability that you will get a sum of 4 before you get a sum of 5 ? (a) (b) (
AlexFokin [52]

Answer:

The probability that you will get a sum of 4 before you get a sum of 5 is \frac{1}{12}

Step-by-step explanation:

Given : If you roll two fair dice repeatedly.

To find : What is the probability that you will get a sum of 4 before you get a sum of 5 ?

Solution :

When two dice are rolled the outcomes are

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

Total number of outcomes = 36

Favorable outcome get a sum of 4 before you get a sum of 5 is (1,3) ,(2,2) and (3,1) = 3

The probability that you will get a sum of 4 before you get a sum of 5 is

P=\frac{3}{36}

P=\frac{1}{12}

Therefore, The probability that you will get a sum of 4 before you get a sum of 5 is \frac{1}{12}

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3 years ago
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