Please help, I don’t know how to do this. Use a compass and straightedge to construct a line perpendicular to the given through
point P
1 answer:
Step-by-step explanation: B
put the center of the circle on the right of the line and the edge of the circle on the p. Make part of a circle. you dont have to do the whole circle, but you can if you want.
do the same thing again but on the other side of the line.
now it should look like the first image i included (if you didnt do the whole circle)
now take your straightedge/ruler/line maker and make it go through the intersecting points on the circles, like the second image.
Note that my images are for demonstration. They're not perfect at all, they're just to show you how to do it.
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Answer:
(5) The perpendicular height of the triangle is 8.48 mm.
(6) The 1184.86 cm far up the wall the ladder reach.
Step-by-step explanation:
Part (5):
When a perpendicular is drawn in an isosceles triangle then the perpendicular divided the base into 2 equal parts.
The figures is shown below.
In ΔABC,
CB = 6 mm
So,
CD = BD = 3 mm
Now calculating the perpendicular height of the triangle.
Using Pythagoras theorem in ΔADC:
Thus, the perpendicular height of the triangle is 8.48 mm.
Part (6):
The figure is shown below.
Converting meter to centimeter:
1 m = 100 cm
So,
12 m = 1200 cm
Using Pythagoras theorem in ΔXYZ:
Thus, 1184.86 cm far up the wall the ladder reach.
