Given:
The equation is
To find:
The solution of the given equation.
Solution:
We have,
It can be written as
Multiply both sides by 7.
Divide both sides by 7.
Therefore, the value of z is -2.
Answer:
80
Step-by-step explanation:
<u><em>A = Area of First Rectangle </em></u>
<u><em>B = Area of Second Rectangle </em></u>
<u><em>w = Width</em></u>
<u></u>
12(w)=320+B (1st Equation)
8(w) = B (2nd Equation)
w=B/8 <em><u>(Plug this value of w into the first equation)</u></em>
12B/8 = 320 +B <u><em>(you get this)</em></u>
12B= 2560 + 8B <u><em>(Simplify)</em></u>
4B = 2560
B =640 <em><u>plug this value into the 2nd equation</u></em>
8(w) = 640
w = 80
<em>To Test This</em>
12x80 = 960
8x80 = 640
<h3>960 - 640 = 320
<u><em>Therefore the answer is correct the width is 80</em></u></h3>
<h3 />
Answer:
Null hypothesis:
Alternative hypothesis:
Since the p value is very low compared to the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true percent of people with type A of blood is significantly different from 0.4 or 40%
Step-by-step explanation:
Information given
n=144 represent the random sample taken
X=81 represent the number of people with type A blood
estimated proportion of people with type A blood
is the value that we want to verify
represent the significance level
z would represent the statistic
![p_v{/tex} represent the p value Hypothesis to testWe want to test if the percentage of the population having type A blood is different from 40%.: Null hypothesis:[tex]p=0.4](https://tex.z-dn.net/?f=p_v%7B%2Ftex%7D%20represent%20the%20p%20value%20%3C%2Fp%3E%3Cp%3E%3Cstrong%3EHypothesis%20to%20test%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3EWe%20want%20to%20test%20if%20the%20percentage%20of%20the%20population%20having%20type%20A%20blood%20is%20different%20from%2040%25.%3A%20%20%3C%2Fp%3E%3Cp%3ENull%20hypothesis%3A%5Btex%5Dp%3D0.4)
Alternative hypothesis:
the statistic is given by:
(1)
Replacing the info given we got:
Now we can calculate the p value with this probability taking in count the alternative hypothesis:
Since the p value is very low compared to the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true percent of people with type A of blood is significantly different from 0.4 or 40%
Answer:
102 would be correct
Step-by-step explanation:
<span>Length, width, and height are all 68 cm.
I am assuming that there's a formatting issue with this question and that the actual size limit is 204 cm. With that in mind, let's create a function giving the width of the box in terms of its height. So
w = (204 - h)/2
Now let's create an expression giving the volume of the box in terms of height.
v = lwh
Since the width and length are the same, replace l with w
v = wwh
And now replace w with (102-h/2)
v = (102-h/2)(102-h/2)h
And expand the equation.
v = (102-h/2)(102-h/2)h
v = (10404 -51h - 51h + 0.25h^2)h
v = (10404 -102h + 0.25h^2)h
v = 10404h -102h^2 + 0.25h^3
Since we're looking for a maximum, that can only happen when the slope of the above equation is equal to 0. The first derivative will tell you the slope of the function at each point. So let's calculate the first derivative. For each term, multiply the coefficient by the exponent and then subtract 1 from the exponent. So:
v = 10404h - 102h^2 + 0.25h^3
v = 10404h^1 - 102h^2 + 0.25h^3
v' = 1*10404h^(1-1) - 2*102h^(2-1) +3*0.25h^(3-1)
v' = 10404h^0 - 204h^1 + 0.75h^2
v' = 10404 - 204h^1 + 0.75h^2
We now have a quadratic equation with A=0.75, B=-204, and C=10404. Use the quadratic formula to find the roots, which are 68 and 204. These 2 zeros represent a local minimum and a local maximum. The value 204 is obviously the local minimum since the box would have a width and length of 0 resulting in a volume of 0. So the height must be 68 which means the length and width are (204 - 68)/2 = 136/2 = 68.
To prove that 68 is the optimal height, let's use a height of (68+e) and see what that does to the volume of the box.
v = (102-h/2)(102-h/2)h
v = (102-(68+e)/2)(102-(68+e)/2)(68+e)
v = (102-(34+e/2))(102-(34+e/2))(68+e)
v = (68-e/2)(68-e/2)(68+e)
v = (4624 - 34e - 34 e + 0.25e^2)(68+e)
v = (4624 - 68e + 0.25e^2)(68+e)
v = 314432 - 4624e + 17e^2 + 4624e - 68e^2 + 0.25 e^3
v = 314432 - 51e^2 + 0.25e^3
Now look at the 2 terms that use e. The -51e^2 term will always be negative, but the +0.25e^3 term will be negative if e is negative and positive if e is positive. So a positive e value (e.g. Make the height larger) does have a possibility of increasing the volume if it can overcome the -51e^2 term. So let's make that equation
0 < -51e^2 + 0.25e^3
51e^2 < 0.25e^3
51 < 0.25e
204 < e
So if we make the height 68 + 204 = 272, then we could have a box with a larger volume. But that's impossible since the largest measurement for any edge is 204 and that's assuming you're willing to set the length of the other 2 dimensions to 0.</span>
