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3 years ago

1 11

Mathematics

1 answer:

Sever21 [200]3 years ago

6 0

The answer is y = 12x - 24

Use the form y = mx + b

If the points are (2, 0) and (3, 12) the slope is 12 which gives us m.

Since every time you go backwards once it goes down 12, (1, -12) is a point and then (0, -24) is a point that shows us the y-intercept which gives us b.

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The diagram shows 5 ft student standing near a tree. The shadow of the student and the shadow of the tree

mariarad [96]

Answer:

x = 25 ft

Step-by-step explanation:

here we see the student standing and creating a small triangle that is equivalent to the big triangle since it has the same angles, the only difference is that its smaller, so what we have to do is make a proportion of both triangles, so since 8 ft correspond with the 40 ft they're going to be in the same part of the proportion and the other measurements, including x, on the other part, so itll be 5/8 and x/40, see how the 8 and 40 are both on the bottom? thats because they correspond, so now all you have to do is cross butterfly, so you can set up an expression on 8x= 5*40 or you can just multiply 5*40 and then divide by 8, your answer will be x= 25 ft

8 0

4 years ago

Read 2 more answers

Which equation has a slope m=2/3

Arisa [49]

Y=(2/3)x+[anything] cause the thing before x is slope

3 0

4 years ago

Write the linearization of the function at the points indicated. (Enter your answer as an equation. Let x be the independent var

Natalija [7]

Answer:

$\displaystyle y=5+\frac{x}{10}$

$\displaystyle y=10+\frac{(x-75)}{20}$

Step-by-step explanation:

<u>Linearization</u>

It consists of finding an approximately linear function that behaves as close as possible to the original function near a specific point.

Let y=f(x) a real function and (a,f(a)) the point near which we want to find a linear approximation of f. If f'(x) exists in x=a, then the equation for the linearization of f is

$y=f(x)=f(a)+f'(a)(x-a)$

Let's find the linearization for the function

$y=\sqrt{25+x}$

at (0,5) and (75,10)

Computing f'(x)

$\displaystyle f'(x)=\frac{1}{2\sqrt{25+x}}$

At x=0:

$\displaystyle f'(0)=\frac{1}{2\sqrt{25+0}}=\frac{1}{10}$

We find f(0)

$f(0)=\sqrt{25+0}=5$

Thus the linearization is

$\displaystyle y=f(0)+f'(0)(x-0)=5+\frac{1}{10}x$

$\displaystyle y=5+\frac{x}{10}$

Now at x=75:

$\displaystyle f'(75)=\frac{1}{2\sqrt{25+75}}=\frac{1}{20}$

We find f(75)

$f(75)=\sqrt{25+75}=10$

Thus the linearization is

$\displaystyle y=f(75)+f'(75)(x-75)=10+\frac{1}{20}(x-75)$

$\displaystyle y=10+\frac{(x-75)}{20}$

5 0

3 years ago

What is the solution? <br><br> -6+x5=6x-7

Margarita [4]

-6 + 5x = 6x - 7 Subtract 5x from both sides
-6 = x - 7 Add 7 to both sides
1 = x Switch the sides to make it easier to read
x = 1

4 0

4 years ago

A student scored 84 and 87 on her first two quizzes.Write and solve a compound inequality to find the possible values for a thir

Varvara68 [4.7K]

Mean of data = sum of values ÷ number of data

We have three values; 84, 87, and $x$

Sum of values = $84+87+x$ = $171+x$

We want the value of $x$ to give mean between 85 and 90 inclusive

$85 \leq \frac{171+x}{3} \leq 90$
$85*3 \leq 171+x \leq 90*3$
$255 \leq 171+x \leq 270$
$255-171 \leq x \leq 270-171$
$84 \leq x \leq 99$

Hence, the value of $x$ is between 84 and 99 inclusive

8 0

3 years ago

Read 2 more answers