For this equation, you want to do it in fractions/ratios to properly solve it. You would have his average misses out of every field goal and his real missed attempts over total. It would look like this

=

You want to solve for x since x is the total amount of field goals that he attempted. You can do this by doing cross multiplication:
(2)(x) = (8)(11)
From here you can get:
2x = 88
Divide each side by 2 to isolate x and you get:
x= 44
So he made a total of 44 field goals.

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Just substract corresponding terms
![\\ \sf\longmapsto \left[\begin{array}{cc}\sf 2 &\sf 3\\ \sf 4&\sf4\\ \sf 8&\sf -5\end{array}\right]](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D%5Csf%202%20%26%5Csf%203%5C%5C%20%5Csf%204%26%5Csf4%5C%5C%20%5Csf%208%26%5Csf%20-5%5Cend%7Barray%7D%5Cright%5D)
Option B
Answer:
4×30+5×30=120+150=270
Step-by-step explanation:
looking at the last row, we can see that the total number of students will be 4×30+5×30=120+150=270
Answer:
1. 401.92 2.6782.4 3. 113,040
Step-by-step explanation:
Answer:
Step-by-step explanation:
Given 
a)
we know that 
therefore 
on integrating we get
c=(1/6640)
b)
on doing the integration we get
=0.37349
c)
marginal density of X is
on doing integration we get
f(x)=(4x+3)/3320 ; 0<x<40
marginal density of Y is
on doing integration we get
d)
solve the above integration we get the answer
e)
solve the above integration we get the answer
f)
Two variables are said to be independent if there jointprobability density function is equal to the product of theirmarginal density functions.
we know f(x,y)
In the (c) bit we got f(x) and f(y)
f(x,y)cramster-equation-2006112927536330036287f(x).f(y)
therefore X and Y are not independent