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MrMuchimi
3 years ago
15

Why is it more secure to require a user to press ctrl+alt+delete to log on rather than displaying the windows welcome screen?

Computers and Technology
1 answer:
Levart [38]3 years ago
5 0
Let's say for example you have a toddler, or a pet. Let's say a cat. If the ctrl+alt+delete wasn't there. It would go straight to entering the password. Now let's say your child or pet likes to press the keys for a while. If they manage to press enter and enter the incorrect password. Eventually it will lock up your computer.
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What happens when you double-click one of the graphic options in the middle panel of the choose a smartart graphic dialog box?
pickupchik [31]
When you open MS Word, selecting the insert option and clicking SmartArt, will pop up SmartArt dialog box. Double-clicking on one of the graphic options in the middle panel will automatically select and place the graphic art you want. It is an easy way of inserting a SmartArt of your choice without selecting the art itself and clicking OK.





3 0
3 years ago
Read 2 more answers
Write a program that prompts the user to enter a series of numbers between 0 and 10 asintegers. The user will enter all numbers
Anna71 [15]

Answer:

The program in Python is as follows:

import collections

from collections import Counter

from itertools import groupby

import statistics

str_input = input("Enter a series of numbers separated by space: ")

num_input = str_input.split(" ")

numList = []

for num in num_input:

         if(num.lstrip('-').isdigit()):

                   if num[0] == "-" or int(num)>10:

                             print(num," is out of bound - rejecting")

                   else:

                             print(num," is valid - accepting")

                             numList.append(int(num))

         else:

                   print(num," is not a number")

print("Largest number: ",max(numList))

print("Smallest number: ",min(numList))

print("Range: ",(max(numList) - min(numList)))

print("Mode: ",end = " ")

freqs = groupby(Counter(numList).most_common(), lambda x:x[1])

print([val for val,count in next(freqs)[1]])

count_freq = {}

count_freq = collections.Counter(numList)

for item in count_freq:

         print(item, end = " ")

         lent= int(count_freq[item])

         for i in range(lent):

                   print("#",end=" ")

print()

Explanation:

See attachment for program source file where comments are used as explanation. (Lines that begin with # are comments)

The frequency polygon is printed using #'s to represent the frequency of each list element

7 0
3 years ago
What do you think is the most important event in the history of the Internet? What event has had the biggest impact on your dail
lana [24]

Answer:the answer would be this serious when anonimous came to the world or rather when anonymity came

 

Explanation:

The most important events of all the Internet was when anonomous arrived and began to reveal secrets and things against the United States government

 

3 0
3 years ago
Your ghost hunting group is recording the sound inside a haunted Stanford classroom for 20 hours as MP3 audio files. About how m
Mademuasel [1]

Answer:

1.152 GB if it will be at 128 kbps quality

Explanation:

So, let's say you choose your mp3 be 128 kbps (kilobits per second).

One byte is 8 bits. So 128 kbps = 16 kilobytes per second.

There is 60*60 seconds in one hour. So 16*60*60 = 57.6 megabytes per hour

Multiply by 20 hours to get your answer: 57.6*20 = 1152 MB = 1.152 GB.

3 0
3 years ago
An array of integers named parkingTickets has been declared and initialized to the number of parking tickets given out by the ci
Sedaia [141]

Answer:

Following code will store the largest value in array parkingTickets in the variable mostTickets

mostTickets = parkingTickets[0];

for(int k = 0; k<parkingTickets.length; k++)

{

if(parkingTickets[i]>mostTickets)

{

 mostTickets = parkingTickets[i];

}

}

Explanation:

In the above code segment, initially the number of tickets at first index is assumed as largest value of tickets in array.

Then using a for loop each value in the array parkingTickets is compared with the current mostTickets value.

If the compared value in parkingTickets array is larger than the current mostTickets value. Then that value is assigned to mostTickets.

This process is repeated for all elements in array.

Thus after looping through each element of array the largest value in array will get stored in mostTickets variable.  

6 0
3 years ago
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