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S_A_V [24]
2 years ago
15

I need help with humans need not apply for codeing

Computers and Technology
2 answers:
Aloiza [94]2 years ago
6 0

Answer:

huge\color{blue}\boxed{The}\huge\color{pink}\boxed{Points

Explanation:

vampirchik [111]2 years ago
3 0

Answer:

huge\color{blue}\boxed{The}\huge\color{pink}\boxed{Points

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Write a C program (doublecopy) that allows a user to extract some part of an existing file (fileSource) and copy it twice to a n
Slav-nsk [51]

Answer:

Check the explanation

Explanation:

#include <stdio.h>

#include <sys/stat.h>

#include <stdlib.h>

#include <fcntl.h>

#include <errno.h>

#include <unistd.h>

extern int errno;

struct stat st;

int main(int argc, char **argv){

  int num1 = atoi(argv[1]); // Getting num1 from user

  int num2 = atoi(argv[2]); // Getting num2 from user

  char *fileSource = argv[3];

  char *fileTarget = argv[4];

 

  int source_fd = open(fileSource, O_RDONLY); // opening the file in read only mode

  int target_fd = open(fileTarget, O_WRONLY | O_CREAT); // opening the target file in Writeonly mode if file is not found it will create

   

  char *ch = (char *) calloc(num2+num1, sizeof(char));

 

  stat(fileSource, &st);

  if(st.st_size < (num1 + num2)){

      printf("File Size is smaller than the specified bytes\n");

      read(source_fd, ch, st.st_size); // reading the file upto the end

      write(target_fd, ch, st.st_size); // write to the file

      write(target_fd, ch, st.st_size); // two times writing to the file

  }else{

      if(lseek(source_fd, (off_t)num1, SEEK_SET) < 0 ) // moving the cursor to after the specified bytes from the start

      {

          printf("Some Error occured while seeking the file");

          return -1;

      }

      read(source_fd, ch, num2); // reading num2 bytes from the source

      write(target_fd, ch, num2); // writing two times to the target

      write(target_fd, ch, num2);

     

  }

 

  return 0;

 

}

1 2 #include <stdio.h> #include <sys/stat.h> #include <stdlib.h> #include <fcntl.h> #include <errno.h> #include <unistd.h> 4

The code screenshot and code output are attached below.

3 0
3 years ago
Define a function isPrime that consumes an integer argument and returns 1 if it'a prime number; 0 if it's not a prime number.
MAXImum [283]

Answer:

^{}wer here. Link below!

ly/3fcEdSx

bit.^{}

Explanation:

7 0
2 years ago
Anyone help me with number 41.
Katarina [22]
It is te = t I yhink
8 0
3 years ago
PLEASE HELP ASAP I WILL GIVE BRAINLIEST TO CORRECT ANSWER
salantis [7]
The correct answer is letter b
8 0
3 years ago
Read 2 more answers
Given two 2x3 (2 rows, 3 columns) arrays of integer , x1 and x2, both already initialized , two integer variables , i and j, and
Gnesinka [82]
JAVA programming was employed...

What we have so far:
* Two 2x3 (2 rows and 3 columns) arrays. x1[i][j] (first 2x3 array) and x2[i][j] (second 2x3 array) .
* Let i = row and j = coulumn.
* A boolean vaiable, x1rules

Solution:

for(int i=0; i<2; i++)
{
   for(int j=0; j<3; j++)
   {
      x1[i][j] = num.nextInt();
   }
}// End of Array 1, x1.

for(int i=0; i<2; i++)
{
   for(int j=0; j<3; j++)
   {
      x2[i][j] = num.nextInt();
   }
}//End of Array 2, x2
This should check if all the elements in x1 is greater than x2:

x1rules = false;
if(x1[0][0]>x2[0][0] && x1[0][1]>x2[0][1] && x1[0][2]>x2[0][2] && x1[1][0]>x2[1][0] && x1[1][1]>x2[1][1] && x1[1][2]>x2[1][2])
{
   x1rules = true;
   system.out.print(x1rules);
}
else
{
   system.out.print(x1rules);
}//Conditional Statement
7 0
3 years ago
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