H=x and b=x+10
A=hb/2 so
A=x(x+10)/2
A=(x^2+10x)/2 and A=48 so
(x^2+10x)=96
x^2+10x-96-0
x^2-6x+16x-96=0
x(x-6)+16(x-6)=0
(x+16)(x-6)=0, since x>0
x=6in, and since the base is x+10
base=16in
Because what please elaborate
Answer:
Denote the cards he had when he started: a
=> 2 x a + 6 = 98
=> 2 x a = 92
=> a = 92/2 = 46
=> He started with 46 cards.
Hope this helps!
:)
This is a composite. Another way to write them is f(g(x)). Take the function g(x) and stick it in for x in f(x). Like this:
![f(g(x))= \frac{(3x+1)-1}{3}](https://tex.z-dn.net/?f=f%28g%28x%29%29%3D%20%5Cfrac%7B%283x%2B1%29-1%7D%7B3%7D%20)
. But we aren't done cuz there's some simplifying there to do.
![f(g(x))= \frac{3x}{3}](https://tex.z-dn.net/?f=f%28g%28x%29%29%3D%20%5Cfrac%7B3x%7D%7B3%7D%20)
and canceling out the 3's we get just a simple x as our answer. The choice is the last one above as your answer.
Answer:
3n^5 (8n^6 +7n +6)
Step-by-step explanation:
24n^11+21n^6+18n^5
Each term has a 3n^5 in it so factor that out
3n^5 (8n^6 +7n +6)