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dusya [7]
2 years ago
11

Need help please!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
const2013 [10]2 years ago
5 0

Answer:

1. 3x = 12 . the answer is d. x = 4

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Graph the following equation using X- and y-intercepts.<br> x + y = -3
Kitty [74]

Answer:

x-intercept: (-3,0)

y-intercept: (0,-3)

Step-by-step explanation:

Looking at the equation, we can see that it is already in standard form, or in a Ax+By=C format. Whenever a line is put into standard form, the x-intercepts are represented by (\frac{C}{A},0) and the y-intercepts are represented by (0, \frac{C}{B} ). So, let's calculate them by doing the following:

1) Find the x-intercept by using the (\frac{C}{A},0) formula. Substitute the number on the right side of the equation for C and the coefficient for the x term for A. So, in this case, C = -3 and A = 1:

(\frac{C}{A},0)\\\\(\frac{-3}{1},0)  \\(-3,0)

Therefore, the x-intercept is (-3,0).

2) Next, find the y-intercept by using the (0,\frac{C}{B} ) formula and substituting the right values. C is still the number on the right side of the equation and B is the coefficient of the y term. So, C = -3 and B = 1.

(0,\frac{C}{B})\\ (0, \frac{-3}{1})\\(0, -3)

Therefore, (0, -3) is the y-intercept.

7 0
3 years ago
Use Algorithm 7 to schedule the largest number of talks in a lecture hall from a proposed set of talks, if the starting and endi
3241004551 [841]

Answer:

If we arrange the talks from the lowest starting time to the highest ending time we get total of 11 talks.

using algorithm 7 we get answer   (1) - (3) - (6) - (9)   the largest number of talks scheduled.

Step-by-step explanation:

arranging the talks from lowest starting time to the highest ending time.

thus,

  1. 9:00 a.m. and 9:45 a.m.
  2. 9:30 a.m. and 10:00 a.m.
  3. 9:50 a.m. and 10:15 a.m.
  4. 10:00 a.m. and 10:30 a.m.
  5. 10:10 a.m. and 10:25 a.m.
  6. 10:30 a.m. and 10:55 a.m.
  7. 10:15 a.m. and 10:45 a.m.
  8. 10:30 a.m. and 11:00 a.m.
  9. 10:45 a.m. and 11:30 a.m.
  10. 10:55 a.m. and 11:25 a.m.
  11. 11:00 a.m. and 11:15 a.m.

we start from the earliest time as

9:00 a.m. and 9:45 a.m which is (1).

After the talk is finished we pick the nearest time for another talk which starts at

9:50 a.m. and 10:15 a.m which is (3).

After this talk we again pick the nearest time for another talk which becomes

10:30 a.m. and 10:55 a.m which is (6).

and lastly

10:45 a.m. and 11:30 a.m which is (9).

Note: we didn't choose other times because we cannot talk at 2 or 3 places at the same time. so we pick another when one talk is finished.

thus the answer is (1) - (3) - (6) - (9) as the largest number of talks scheduled.

4 0
4 years ago
The table shows the relationship between the number of Calories Tai burns while biking and the number of minutes he bikes. Minut
tensa zangetsu [6.8K]
6 calories

divide calories burned by minutes biking to get average calories burned per minute
8 0
4 years ago
Read 2 more answers
What is the slope of 2x + y = 5​
vitfil [10]

2. the slope is 2 because

8 0
4 years ago
Read 2 more answers
Select the best name for this figure.
noname [10]

Answer:

A

I hope this will help you.

5 0
3 years ago
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