Subtracting or adding multiples of 2*r to any angle will make no change, it will be the same angle.
7*pi/6 = 6*pi/6 + pi/6
So, the angle is in the third quadrant and surpasses pi radians by pi/6 radians or 30 degrees.
The positive co-terminal angles are:
Adding 2*pi,
7*pi/6 + 12*pi/6 = 19*pi/6
Adding another 2*pi,
7*pi/6 + 2*(12*pi)/6 = 7*pi/6 + 24*pi/6
7*pi/6 + 24*pi/6 = 31*pi/6
The 2 negative co-terminal angles are:7*pi/6 – 12*pi/6 = 5*pi/6
And
7*pi/6 – 24*pi/6 = -17*pi/6
Answer:
S(t) = -4.9t^2 + Vot + 282.24
Step-by-step explanation:
Since the rocket is launched from the ground, So = 0 and S(t) = 0
Using s(t)=gt^2+v0t+s0 to get time t
Where g acceleration due to gravity = -4.9m/s^2. and
initial velocity = 39.2 m/a
0 = -4.9t2 + 39.2t
4.9t = 39.2
t = 8s
Substitute t in the model equation
S(t) = -49(8^2) + 3.92(8) + So
Let S(t) =0
0 = - 313.6 + 31.36 + So
So = 282.24m
The equation that can be used to model the height of the rocket after t seconds will be:
S(t) = -4.9t^2 + Vot + 282.24
Answer:
A is the right anwser and the most reasonable.
Step-by-step explanation:
Answer:
Step-by-step explanation: