Prove that the diagonals of a parallelogram bisect each other.
1 answer:
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Which equation represents the line that passes through (–8, 11) and (4,7/2 )?
☆☆☆☆☆☆☆☆☆☆☆☆☆☆A. y =-5/8x + 6
B.y =-5/8 x + 16
C. y = -15/2x – 49
D. y =-15/2 x + 71
☆☆☆☆☆☆☆☆☆☆☆☆☆☆A. y =-5/8x + 6
B.y =-5/8 x + 16
C. y = -15/2x – 49
D. y =-15/2 x + 71
That's an easy parallelogram, parallel to the x axis. Let's label the points
A(-4,-1),B(-2,4),C(4,4),D(2,-1)
AD and BC are the sides parallel to the x axis. We'll call those the base, it has length 4 - -2 = 6.
The height is the change in y between the bases, so 4 - -1 = 5.
The area is base times height, 6 × 5 = 30
Answer: 30
The shoelace formula gives us the area of a polygon from 2D coordinates without worrying about the shape:
(-4,-1),(-2,4),(4,4),(2,-1)
(-2,4),(4,4),(2,-1),(-4,-1)
Answer:
R
H
S
= cos
2
x
Step-by-step explanation:
