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masya89 [10]
4 years ago
6

Prove that the diagonals of a parallelogram bisect each other.

Mathematics
1 answer:
lutik1710 [3]4 years ago
4 0

Answer:2a + 2b, 2c

Step-by-step explanation:

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Four students simplify the expression below: 6 + 4 x 10 ÷ 2 Anshu's solution is 25 , David's solution is 46 , Jimmy's solution i
Mrac [35]

Answer:

Jimmy; 26

Step-by-step explanation:

PEMDAS

Parentheses Exponents Multiplication Division Addition Subtraction

6 + 4 * 10 / 2 = 6 + 40 / 2

6 + 40 / 2 = 6 + 20

6 + 20 = 26

26

7 0
3 years ago
A person must score in the upper 8% of the population on an IQ test to qualify for membership in MENSA, the international high-I
Cloud [144]

Answer:

A person must get an IQ score of at least 138.885 to qualify.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 115, \sigma = 17

(a). [7pts] What IQ score must a person get to qualify

Top 8%, so at least the 100-8 = 92th percentile.

Scores of X and higher, in which X is found when Z has a pvalue of 0.92. So X when Z = 1.405.

Z = \frac{X - \mu}{\sigma}

1.405 = \frac{X - 115}{17}

X - 115 = 17*1.405

X = 138.885

A person must get an IQ score of at least 138.885 to qualify.

5 0
3 years ago
Read 2 more answers
If LM = 20 cm, and PQ = 16 cm, what is the length of RM, in centimeters?
LuckyWell [14K]

Answer:

RM = 12 cm

Step-by-step explanation:

a^{2} + b^{2} = c^{2}

Assuming 20 is the hypotenuse cus there is no picture:

a^{2} + 16^{2} = 20^{2}

a^{2} +256 = 400

a^{2} = 144

a=144

If It's not the hypotenuse:

16^{2}+ 20^{2} =c^{2}

256+400 =c^{2}

656=c^{2}

c = 25.61249695

But I find it unlikely that 20 wasn't the hypotenuse so ignore that unless it applies.

Hope this helped. :0)

5 0
3 years ago
PLEASE HELP, WILL MARK BRAINLIEST - Jessie graphed one of the lines in a system of equations: y=3x-2. If the system has an infin
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B, D, and E are all correct. The line is coinciding.
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