The rate of deceleration is equal to 25 m/s / 6 s = 25/6 m/s^2.
(a) The string should be angled in such a way that the horizontal acceleration is equal to 25.6 and the vertical acceleration is equal to gravitational acceleration. Using trigonometry,Angle from the vertical = arctan(25/6 / 9.8) = 23.03 degrees.
(b) Since the car is decelerating, one end of the string attached to the car is pulled back and because of the inertia of the object it is goes on the opposite direction and so the object moves toward the windshield.
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AB, CA, BC hope this helps
The slope of the tangent line to the curve at (8, 2) is given by the derivative 
at that point. By the chain rule,
Differentiate the given parametric equations with respect to 
:
Then
We have 
and 
when 
, so the slope at the given point is 
.
The normal line to the same point is perpendicular to the tangent line, so its slope is +4. Then using the point-slope formula for a line, the normal line has equation
Alternatively, we can eliminate the parameter and express 
explicitly in terms of 
:
Then the slope of the tangent line is
At 
, the slope is again 
, so the normal has slope +4, and so on.
The correct scale factor is 3 :)
Your answer is 59.
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