Answer:
The equation has two solutions for x:
<u>x₁ = (8 + 10i)/2</u>
<u>x₂ = (8 - 10i)/2</u>
Step-by-step explanation:
Let's use the quadratic formula for solving for x in the equation:
X^2 - 8X + 41= 0
x² - 8x + 41 = 0
Let's recall that the quadratic formula is:
x = -b +/- (√b² - 4ac)/2a
Replacing with the real values, we have:
x = 8 +/- (√-8² - 4 * 1 * 41)/2 * 1
x = 8 +/- (√64 - 164)/2
x = 8 +/- (√-100)/2
x = 8 +/- (√-1 *100)/2
Let's recall that √-1 = i
x = 8 +/- 10i/2
<u>x₁ = (8 + 10i)/2</u>
<u>x₂ = (8 - 10i)/2</u>
The answer is C; 35.5 units^2
Answer:the answer is a 17psi
Step-by-step explanation:
This is always ''interesting'' If you see an absolute value, you always need to deal with when it is zero:
(x-4)=0 ===> x=4,
so that now you have to plot 2 functions!
For x<= 4: what's inside the absolute value (x-4) is negative, right?, then let's make it +, by multiplying by -1:
|x-4| = -(x-4)=4-x
Then:
for x<=4, y = -x+4-7 = -x-3
for x=>4, (x-4) is positive, so no changes:
y= x-4-7 = x-11,
Now plot both lines. Pick up some x that are 4 or less, for y = -x-3, and some points that are 4 or greater, for y=x-11
In fact, only two points are necessary to draw a line, right? So if you want to go full speed, choose:
x=4 and x= 3 for y=-x-3
And just x=5 for y=x-11
The reason is that the absolute value is continuous, so x=4 works for both:
x=4===> y=-4-3 = -7
x==4 ====> y = 4-11=-7!
abs() usually have a cusp int he point where it is =0
Hope it helps, despite being this long!
Answer:
1. 3-4-5 method
2. Rope method
3. Optical square method
Step-by-step explanation:
1. A measuring tape, two ranging poles, pegs and three person's are needed.
First person holds together btw thumbs and finger the zero mark, the second person holds between thumb and finger the 3m mark on the tape and the third person holds the 8m, when all sides of the rope are stretched, a triangle is formed and angle near one is a right angle.
2. One loop of the rope is placed around peg A with a peg through other loop make a circle on the ground place peg B & C where circle crosses the base line and peg D is place half way between peg B & C, allowing peg D & A to form lines perpendicular to base line thereby forming a right angle.
3 this are simple instruments used to set out right angles and they are single and double prismatic square.
