Evaluate

Mary's dog weighs 185 pounds. Her dog needs to lose between 9 and 15 pounds. Between what two percentages, rounded to the neares

Kobotan [32]

Answer:

5-8% of the weight

Step-by-step explanation:

The dog needs to lose a weight within the values 9-15 pounds

To answer this question, what we just need to do is to know the percentage of 185 pounds that is 9 and the percentage of 185 pounds that is 15

The percentage decrease can be calculated using the formula;

(difference)/old value * 100%

For the 9 pound loss, we have ;

9/185 * 100% = 4.86 which is approximately 5%

For the 15 pound loss, we have;

15/185 * 100% = 8.11% which is approximately 8%

Thus, the dog is losing between 5-8% of its weight

6 0

2 years ago

to make a sandwich steve uses 1/8 Ib of ham and 1/5 Ib of cheese. How much more cheese than ham does he use

mote1985 [20]

1/5-1/8= 3/40 Hope it helps <3

6 0

2 years ago

Read 2 more answers

A beachfront hotel is planning for its summer busy season. It wishes to estimate with 95% confidence the average number of night

Kamila [148]

Answer:

0.1369

(4.732, 5.268)

Step-by-step explanation:

Given that:

Mean, m = 5

Standard deviation, s = 1.5

Error margin, E = 0.5

Sample size, n = 120

Zcritical at 95% = 1.96

Standard Error of the mean (S. E) :

S. E = s /sqrt(n)

S. E = 1.5 / sqrt(120

S.E = 1.5 / 10.954451

S. E = 0.1369306

S. E = 0.1369

Confidence interval (C. I)

Mean ± (Zcritical * S.E)

5 ± (1.96 * 0.1369)

Lower boundary = 5 - 0.268324 = 4.731676

Upper boundary = 5 + 0.268324 = 5.268324

(4.732, 5.268)

5 0

2 years ago

A rocket is launched from a tower. The height of the rocket, y in feet, is rel

VikaD [51]

9514 1404 393

Answer:

9.70 seconds

Step-by-step explanation:

The zero of the equation can be found using the quadratic formula.

ax² +bx +c = 0

x = (-b ±√(b² -4ac))/(2a)

We are only interested in the positive value of x, so this will be ...

x = (-147 -√(147² -4(-16)(80)))/(2(-16)) = (147 +√2679)/32

x ≈ 9.7028 ≈ 9.70 . . . . seconds

The rocket will hit the ground after about 9.70 seconds.

6 0

2 years ago

Solve <img src="https://tex.z-dn.net/?f=2%20cosx%3D4cosx%20sin%5E2x" id="TexFormula1" title="2 cosx=4cosx sin^2x" alt="2 cosx=4c

Ilia_Sergeevich [38]

There are four solutions for the trigonometric equation 2 · cos x = 4 · cos x · sin² x are x₁ = π/4 ± 2π · i, x₂ = 3π/4 ± 2π · i, x₃ = 5π/4 ± 2π · i and x₄ = 7π/4 ± 2π · i, $i \in \mathbb{N}_{O}$ .

<h3>How to solve a trigonometric equation</h3>

In this problem we must simplify the trigonometric equation by both algebraic and trigonometric means and clear the variable x:

2 · cos x = 4 · cos x · sin² x

2 · sin² x = 1

sin² x = 1/2

sin x = ± √2 /2

There are several solutions:

x₁ = π/4 ± 2π · i, $i \in \mathbb{N}_{O}$

x₂ = 3π/4 ± 2π · i, $i \in \mathbb{N}_{O}$

x₃ = 5π/4 ± 2π · i, $i \in \mathbb{N}_{O}$

x₄ = 7π/4 ± 2π · i, $i \in \mathbb{N}_{O}$

There are four solutions for the trigonometric equation 2 · cos x = 4 · cos x · sin² x are x₁ = π/4 ± 2π · i, x₂ = 3π/4 ± 2π · i, x₃ = 5π/4 ± 2π · i and x₄ = 7π/4 ± 2π · i, $i \in \mathbb{N}_{O}$ .

To learn more on trigonometric equations: brainly.com/question/27821667

#SPJ1

4 0

1 year ago