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Nostrana [21]
3 years ago
11

Evaluate

Mathematics
2 answers:
oee [108]3 years ago
3 0

Answer:

-1

Step-by-step explanation:

-2+(-1)÷3

-2-1÷3

-3÷3

-1

o-na [289]3 years ago
3 0

Answer:

-2+(-1)

= -----------

3

-2-1

= ------------

3

-3

= --------

3

= -1

Step-by-step explanation:

substitute the letters with the given numbers

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Find the Ratio of 1 hour and 45 minutes​
Paladinen [302]
1 hour = 60 minutes
1 hour:45 minutes
= 60 minutes:45 minutes
=12 minutes:9 minutes
4 0
4 years ago
Read 2 more answers
What does -22 belong to
Len [333]

Answer:

it's part of the real number system

it's a rational number

it's an integer

Step-by-step explanation:

6 0
3 years ago
What is 917 divided by 9 equal? Show the work.
icang [17]
900/9= 100
9/9= 1
17-9=8
8/9 = 0.8888
101.888888
or rounded 101.89
3 0
3 years ago
A sample size 25 is picked up at random from a population which is normally
Margarita [4]

Answer:

a) P(X < 99) = 0.2033.

b) P(98 < X < 100) = 0.4525

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 100 and variance of 36.

This means that \mu = 100, \sigma = \sqrt{36} = 6

Sample of 25:

This means that n = 25, s = \frac{6}{\sqrt{25}} = 1.2

(a) P(X<99)

This is the pvalue of Z when X = 99. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{99 - 100}{1.2}

Z = -0.83

Z = -0.83 has a pvalue of 0.2033. So

P(X < 99) = 0.2033.

b) P(98 < X < 100)

This is the pvalue of Z when X = 100 subtracted by the pvalue of Z when X = 98. So

X = 100

Z = \frac{X - \mu}{s}

Z = \frac{100 - 100}{1.2}

Z = 0

Z = 0 has a pvalue of 0.5

X = 98

Z = \frac{X - \mu}{s}

Z = \frac{98 - 100}{1.2}

Z = -1.67

Z = -1.67 has a pvalue of 0.0475

0.5 - 0.0475 = 0.4525

So

P(98 < X < 100) = 0.4525

6 0
3 years ago
L<br> E<br> N<br> 4<br> 8<br> 1<br> O<br> k<br> M<br> What is the value of k?<br> k=
s2008m [1.1K]

Answer: 2

Step-by-step explanation:

By the geometric mean theorem,

\sqrt{8k}=4\\\\8k=16\\\\k=\boxed{2}

6 0
2 years ago
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