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Juliette [100K]
3 years ago
10

Listed below are pulse rates​ (beats per​ minute) from samples of adult males and females. Does there appear to be a​ difference

? Find the coefficient of variation for each of the two​ samples; then compare the variation.
Male Female89 6871 8060 8068 7070 7650 8662 8756 8482 8768 8762 9461 70100 8756 8165 77
Mathematics
2 answers:
tiny-mole [99]3 years ago
6 0

Answer / Step-by-step explanation:

FOR MALE

Mean for male pulse rate:

Xˣ = ∑ x / n

86 + 72 + 64 + 72 + 72 + 54 + 66 + 56 + 80 + 72 + 64 + 64 + 96 + 58 + 66 / 15

= 1042 / 15

= 69.4667

Approximately, we have = 69.5

Variance for the male pulse rate:

S² = ∑ (x - xˣ )² / n - 1

= (86 - 69.5)² +  (72 - 69.5)² +  (64 - 69.5)² +  (72 - 69.5)² +  (72 - 69.5)² +  (54 - 69.5)² +  (66 - 69.5)² +  (56 - 69.5)² +  (80 - 69.5)² +  (72 - 69.5)² +  (64 - 69.5)² +  (64 - 69.5)² +  (96 - 69.5)² +  (58 - 69.5)² +  (66 - 69.5)² / 15 - 1

= 272.25 + 6.25 + 30.25 + 6.25 + 6.25 + 240.25 + 12.25 + 182.25 + 110.25 + 6.25 + 30.25 + 702.25 + 132.25 + 12.25 / 14

= 1779.75 / 14

127 . 12

Standard Deviation for the male pulse rate:

S =  √ ∑ n ( ∑ x² )  - (∑ x )² / n (n - 1)

Therefore, s = √s²

S = √ 127.12

S = 11.3

Coefficient of variation:

CV = S / X

= 11.2749 / 69.4667

= 0.1623. Converting to percentage, we have: 16.23%

FOR FEMALE

Mean for Female pulse rate:

Xˣ = ∑ x / n

= 64 + 84 + 82 + 70 + 74 + 86 + 90 + 88 + 90 + 90 + 94 + 68 + 90 + 82 + 80 / 15

= 1232 / 15

= 82 . 1333

Variance for the female pulse rate:

S² = ∑ (x - xˣ )² / n - 1

= (64 - 82.1333)² + (84 - 82.1333)² + (82 - 82.1333)² + (70 - 82.1333)² + (74 - 82.1333)² + (86 - 82.1333)² + (90 - 82.1333)² + (88 - 82.1333)² + (90 - 82.1333)² + (90 - 82.1333)² + (94 - 82.1333)² + (68 - 82.1333)² + (90 - 82.1333)² + (82 - 82.1333)² + (80 - 82.1333)² / 15 - 1

Calculating further, we arrive at

= 84.8381

Standard Deviation for the female pulse rate:

S =  √ ∑ n ( ∑ x² )  - (∑ x )² / n (n - 1)

Therefore, s = √s²

S = √  84.8381

S = 9.2108

Coefficient of variation:

CV = S / X

= 9.2108 / 82.1333

= 0.1121. Converting to percentage, we have: 11.21%

Now, to compare, we can see that the variation for female pause rate appears to be lower than the variation for male pulse rate.

MrMuchimi3 years ago
5 0

Answer:

There appears to be a difference between the pulse rates from samples of adult males and females. The average pulse rate of males is 63.75 while that of females is 75.875.

Coefficient of Variation (male) = 33.44%

Coefficient of variation (female) = 28.35%

Step-by-step explanation:

Mean (male) = \frac{sum of x}{n} =\frac{1020}{16} =63.75

Mean (female) = \frac{sum of y}{n} = \frac{1214}{16} = 75.875

Standard Deviation (male) = \sqrt{\frac{sum(x-63.75)^2}{16-1} } =21.315

Standard Deviation (female) = \sqrt{\frac{sum(y-75.875)^2}{16-1} } = 21.512

Coefficient of Variation  = \frac{Std dev}{mean} *100

For male, CV = \frac{21.315}{63.75} *100=33.44%%

For female, CV = \frac{21.512}{75.875} *100=28.35%

Comparison : Pulse rates of males has more variability than that of females since it has a greater coefficient of variation.

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