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3 years ago

You roll a 6 sided cube, what is the probability of rolling a multiple of 2 or a number greater than 3?

Mathematics

2 answers:

vova2212 [387]3 years ago

7 0

The probability of rolling a multiple 2 or a number greater than 3 is 1/3

Marina CMI [18]3 years ago

5 0

Okay so here we go,

Multiples of 2 on a 6 sided cube are:
2, 4 and 6 which in probability terms is 3/6 (simplifies to 1/2)

Numbers greater than 3 are: 4, 5 and 6 which in probability terms is 3/6 (simplifies to 1/2)

The question says 'or' which means addition of probabilities.

1/2 + 1/2 = 1
Your answer is 1

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(0.053) (0.578)<br> Multiply the numbers

Crazy boy [7]

Answer:

If you multiply the numbers you will get

0.030634

5 0

3 years ago

Find mZPQR.<br> help asap

DENIUS [597]

<h3>Answer: D) 72</h3>

======================================

Work Shown:

Angle PQR = (far arc - near arc)/2

2x+72 = ( (2x+252) - (2x+108) )/2

2x+72 = 144/2

2x+72 = 72

2x = 72-72

2x = 0

x = 0/2

x = 0

-------------

Angle PQR = 2x+72

Angle PQR = 2(0)+72

Angle PQR = 72 degrees

4 0

3 years ago

A student solved this problem and said the answer is about 7 quarts. Eddie has paint left over from a project. He has 2 fraction

kati45 [8]

The anwser would be C. trust me i just took this test

5 0

4 years ago

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A faraway planet is populated by creatures called Jolos. All Jolos are either green or purple and either one-headed or two-heade

enyata [817]

A. 260

Explanation

Step 1

Let

$\begin{gathered} green\text{ jolos,one-headed jolo=170} \\ \text{Purple ,two-headed jolos=284} \\ one\text{ headed jolos=430} \end{gathered}$

as we can see

the total of green-one headed jolo is 170

and the total for one headed jolo is =430

so, the one-headed in counted twice

$\begin{gathered} total\text{ of gr}en\text{ jolos= }430-170 \\ total\text{ of gr}en\text{ jolos= }260 \end{gathered}$

so, the answer is

A.260

I hope this helps you

8 0

1 year ago

Find the product of the complex number and its conjugate. 3 + 3i

irina1246 [14]

First, we are going to find the conjugate of our complex number. Remember that to find the conjugate of a complex number we just need to keep the real part and change the sing of the imaginary part.

We can infer from our problem that the real part of our complex number is 3 and its imaginary part is $3i$ . We are going to keep the real part 3 and change the imaginary part from positive to negative, so our conjugate is $3-3i$ .

Next, we are gong to multiply both the complex number and its conjugate using the distributive property:

$(3+3i)(3-3i)=(3*3)-(3*3i)+(3*3i)-(3i*3i)=9-9i+9i-9i^2=9-9i^2$

Remember that $i^2=\sqrt{-1}^{2} =-1$ , so:

$9-9i^2=9-9(-1)=9+9=18$

We can conclude that the product of the multiplication of the complex number 3+3i and its conjugate, 3-3i, is 18.

6 0

4 years ago

Read 2 more answers