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3 years ago

In cross-sectional studies, the midlife period is characterized by

2 answers:

8 0

In the cross-sectional studies, midlife period is often characterized by an increase in environmental theory which is then the answer. Carl Jung called Middle age as the afternoon of life. Midlife is the period from 40 to 65.In this time adults may think in reassessing their professions while they have time still.

storchak [24]3 years ago

7 0

Answer:

increases in environmental mastery.

Explanation:

Cross-sectional study is defined by observational research, which analyzes data collected over a period of time. This survey can be in a sample population or in a predefined subset. This type of study is also known as cross-sectional study, cross-sectional study and prevalence study. The data collected in the cross-sectional study are from similar people in all variables. Except for the variable being studied.

Regarding middle age, cross-sectional studies are characterized by increases in the environmental domain as a shared feature among participants and research in this approach.

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3 years ago

________ is frequently caused by hearing loss, loud noises, medicines, and other health problems, such as allergies, tumors, and

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4 years ago

Which two processes increase GENETIC<br> VARIATION?

igomit [66]

Answer:

Mutations and crossing over during sexual reproduction

Explanation:

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5 0

3 years ago

Read 2 more answers

Will give a brainiest for the answer thanks :)

Stella [2.4K]

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3 years ago

A research team studies a large Eastern Milk Snake population in a metropark. In these snakes, gene T is one gene that affects t

sweet [91]

Answer:

Option E

Explanation:

As per Hardy Weinberg's second equation of equilibrium, the sum of genotype frequency for all possible genotype in a given population with two allele is equal to

$p^2 + q^ 2+2pq = 1\\$

Substituting the given values in above equation, we get -

$0.16 + 0.64 + 0.20 =1\\ p^2+q^2+2pq= 1$

Hence, second equation satisfies.

As per Hardy Weinberg's first equation of equilibrium, sum of all allele frequencies is equal to 1

$p + q=1\\\sqrt{0.16} +\sqrt{0.64} \\0.4+0.8 = 1.2\neq 1$

Hence, this population is not in Hardy weinberg's equation.

After one generation, the frequency of T allele is $0.4$ which is the same as that of frequency of T allele in previous generation

Also as per hardy Weinberg's theory , if a population genotype frequency sums up to 1, it is in equilibrium if its allele frequency sum is also 1.

But here in 2004. This was not the case.

However, Weinberg has stated that the population which is not in equilibrium can reach equilibrium after one generation only with a new set of genotype frequency and allele frequencies.

Hence, in this case there is a possibility that allele and genotype frequencies have readjusted to sum up to 1

If frequency of the T allele is $0.4$

New frequency of the t allele would be

$1- 0.4\\= 0.6$

and New genotype frequencies would be

$p^ 2 = 0.4^2 = 0.16\\q^ 2 = (1-0.4)^2 = 0.36\\2pq = 1-0.16-0.36 = 0.48$

Thus, $p^ 2+q^2+2pq = 1$

Hence, option E is correct

5 0

3 years ago