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4 years ago

Write the ratio two fifths to 8 as a fraction in simplest form. PLEASE HELP

Mathematics

1 answer:

charle [14.2K]4 years ago

7 0

Answer:

the answer is b on oddesseyware

Step-by-step explanation:

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Express (1)/(2\sqrt(2)) as a power of 2

Sphinxa [80]

$( \frac{1}{2 \div \sqrt{2} }) {}^{2} \\t aking \: square \: we \: get \\ \frac{ {1}^{2} }{2 {}^{2} \div ( { \sqrt{2} })^{2} } \\ = \frac{1}{4 \div 2} = \frac{1}{2}$

5 0

3 years ago

HELP i will give brainliest all questions ;(

Rama09 [41]

Answer:

1. The theoretical probability of rolling an even number and flipping heads is 25%.

2. The experimental probability of rolling a 1 and flipping tails is 15%.

3. The experimental probability of flipping heads is 40%.

4. I think around 7%.

5. I would expect to roll 3 and land on heads 8 times.

Step-by-step explanation:

I am not sure about number 4.

Have a nice day!

Ask me if you need my work. :-)

8 0

3 years ago

Write each number in scientific notation 1 27.5

babymother [125]

1 = 1 x 10 exponent 0
27.5 = 2.75 x 10 exponent 1

8 0

3 years ago

Read 2 more answers

A Flagpole casts a shadow 32 feet long. If a man is 6 feet tall casts a shadow 8 feet long at the same time and location. How ta

Kaylis [27]

24 feet
Set up a ratio of object height to shadow length.
So x/32=6/8
8(4)=32 so 6(4) would be 24.

4 0

3 years ago

In an effort to estimate the mean of amount spent per customer for dinner at a major Lawrence restaurant, data were collected fo

larisa86 [58]

Answer:

The 99% confidence interval for the population mean is 22.96 to 26.64

Step-by-step explanation:

Consider the provided information,

A sample of 49 customers. Assume a population standard deviation of $5. If the sample mean is $24.80,

The confidence interval if 99%.

Thus, 1-α=0.99

α=0.01

Now we need to determine $z_{\frac{\alpha}{2}}=z_{0.005}$

Now by using z score table we find that $z_{\frac{\alpha}{2}}=2.58$

The boundaries of the confidence interval are:

$\mu-z_{\frac{\alpha}{2}}\times \frac{\sigma}{\sqrt{n} }\\24.80-2.58\times \frac{5}{\sqrt{49}}=22.96\\\mu+z_{\frac{\alpha}{2}}\times \frac{\sigma}{\sqrt{n} }\\24.80+2.58\times \frac{5}{\sqrt{49}}=26.64$

Hence, the 99% confidence interval for the population mean is 22.96 to 26.64

3 0

4 years ago