Answer:
a) 81.5%
b) 95%
c) 75%
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 266 days
Standard Deviation, σ = 15 days
We are given that the distribution of length of human pregnancies is a bell shaped distribution that is a normal distribution.
Formula:

a) P(between 236 and 281 days)

b) a) P(last between 236 and 296)

c) If the data is not normally distributed.
Then, according to Chebyshev's theorem, at least
data lies within k standard deviation of mean.
For k = 2

Atleast 75% of data lies within two standard deviation for a non normal data.
Thus, atleast 75% of pregnancies last between 236 and 296 days approximately.
y - 1 = ⁵/₆(x - 4)
y - 1 = ⁵/₆(x) - ⁵/₆(4)
y - 1 = ⁵/₆x - 3¹/₃
+ 1 + 1
y = ⁵/₆x - 2¹/₃
⁻⁵/₆x + y = ⁵/₆x - ⁵/₆x - 2¹/₃
-6(⁻⁵/₆x + y) = -6(-2¹/₃)
-6(⁻⁵/₆x) - 6(y) = 14
5x - 6y = 14
Answer:
Step-by-step explanation:
Given
Two sides of triangle of sides 5 ft and 7 ft
and angle between them is increasing at a rate of 0.9 radians per second
let
is the angle between them thus
Area of triangle when two sides and angle between them is given


Differentiate w.r.t time

at 


It has to be 36 because it the same stick as the other stick that is telling 36
Answer:
7,515
Step-by-step explanation: