Answer:
208 ft^3
Step-by-step explanation:
Let the plane through the 4 ft X 4ft square at the top of the figure break the figure into 2 boxes, one has dimensions (8-7) by 3 by 4 = 1ft X 3ft X 4ft, and the other has dimensions 7 by 7 by 4 = 7ft X 7ft X 4ft.
They have volumes of (1)(3)(4) = 12 ft^3, and (7)(7)(4) = 196 ft^3, respectively, so the total volume = 12 + 196 = 208 ft^3, the answer.
Answer:
Rhombus Side = sqr root [(34 / 2)^2 + (30 / 2)^2]
Rhombus Side = sqr root [17^2 + 15^2]
Rhombus Side = sqr root [289 + 225}
Rhombus Side = sqr root [514]
Rhombus Side = 22.6715680975
Rhombus Perimeter = side * 4 = 90.68627239 cm
Step-by-step explanation:
I think that the answer is A) because the range is y.