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3 years ago

When it says how many fewer in math what does it mean?

Mathematics

2 answers:

vovikov84 [41]3 years ago

8 0

Fewer, less, less than, decreased, decrease by they all mean subtract!

fredd [130]3 years ago

5 0

Fewer typically means subtraction in math.

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Solve. <br><br>2+4y=y−7 <br><br>y=−1/3 <br>y=−1 <br>y=−3<br> I don't know.

vesna_86 [32]

I believe it’s -3 because it just sound realistic

5 0

3 years ago

PLEASE HELP 3x – 7 ≥ 4x + 2

sleet_krkn [62]

Hi there!

$\large\boxed{x \leq -9}$

3x - 7 ≥ 4x + 2

Subtract 3x from both sides:

3x - 3x - 7 ≥ 4x - 3x + 2

-7 ≥ x + 2

Subtract 2 from both sides:

-7 - 2 ≥ x + 2 - 2

-9 ≥ x

x ≤ -9

4 0

3 years ago

Point A (6,2) is translated using the vector <-5,2>. Where is the new point located?

Dominik [7]

<h3>Answer: (1,4)</h3>

======================================================

Explanation:

The notation <-5,2> is the same as writing the translation rule $(x,y) \to (x-5,y+2)$

It says: move 5 units to the left and 2 units up

The point (6,2) moves to (1,2) when moving five units to the left. Then it ultimately arrives at (1, 4) after moving 2 units up. You could move 2 units up first and then 5 units to the left later on, and you'd still arrive at (1, 4). In this case, the order doesn't matter (some combinations of transformations this won't be the case and order will matter).

---------

Or you could write out the steps like so

$(x,y) \to (x-5, y+2)\\\\(6,2) \to (6-5, 2+2)\\\\(6,2) \to (1, 4)\\\\$

We see that (6,2) moves to (1, 4)

4 0

3 years ago

Help me with another math question, thank you very much

Alika [10]

Answer:

Step-by-step explanation:

X is the exponent in the equation

4 0

3 years ago

Read 2 more answers

s) An e-mail lter is planned to separate valid e-mails from spam. The word free occurs in 50% of the spam messages and only 3% o

balu736 [363]

Answer:

A) P(F) = 0.124

B) P(S|F) = 0.8065

C) P(V|F^(c)) = 0.886

Step-by-step explanation:

Let us denote as follows;

F = Message contains word free

S = message is spam

V = message is valid

From the question, we are given that;

The probability that word free occurs in spam messages;P(F|S) = 50% = 0.5

The probability of the valid messages that contain free; P(F|V) = 3% = 0.03

Spam messages; P(S) = 20% = 0.2

Valid messages; P(V) = 1 - 0.2 = 0.8

A) From rule of total probability ;

probability that the message contains the word free is given as;

P(F) = P(F|S)•P(S) + P(F|V)•P(V)

P(F) = (0.5 x 0.2) + (0.03 x 0.8)

P(F) = 0.124

B) From Baye's theorem;

probability that the message is spam given that it contains free is given as;

P(S|F) = P(F|S)•P(S)/P(F)

P(S|F) = (0.5 x 0.2)/0.124

P(S|F) = 0.8065

C) From combination of complement rule and Baye's theorem;

probability that the message is valid given that it does not contain free is given as;

P(V|F^(c)) = P(F^(c)|V)•P(V)/P(F^(c))

Thus,

P(V|F^(c)) = [(1 - P(F|V))•P(V)]/(1 - P(F))

P(V|F^(c)) = ((1 - 0.03)•0.8)/(1 - 0.124)

P(V|F^(c)) = 0.776/0.876

P(V|F^(c)) = 0.886

5 0

4 years ago