I think you probably meant <span>(x+2)^2+4 because the equation you have provided is not written in proper formatting and would actually be a straight line. However, if you meant for that second 2 to be an exponent, you now have a quadratic equation which would graph as a parabola. Remember the basic formula is y=(x-h)^2 +k where (h,k) is your vertex. So you change the sign of the number in the parenthesis, but not the number outside the parenthesis when finding the vertex. If there is a negative number in front of your equation, then the parabola is flipped upside down so the vertex would be a maximum, but if it is positive, or has nothing in front of it, then the parabola sits up like a bowl so the vertex is a minimum.</span>
Answer:
9·x² - 36·x = 4·y² + 24·y + 36 in standard form is;
(x - 2)²/2² - (y + 3)²/3² = 1
Step-by-step explanation:
The standard form of a hyperbola is given as follows;
(x - h)²/a² - (y - k)²/b² = 1 or (y - k)²/b² - (x - h)²/a² = 1
The given equation is presented as follows;
9·x² - 36·x = 4·y² + 24·y + 36
By completing the square, we get;
(3·x - 6)·(3·x - 6) - 36 = (2·y + 6)·(2·y + 6)
(3·x - 6)² - 36 = (2·y + 6)²
(3·x - 6)² - (2·y + 6)² = 36
(3·x - 6)²/36 - (2·y + 6)²/36 = 36/36 = 1
(3·x - 6)²/6² - (2·y + 6)²/6² = 1
3²·(x - 2)²/6² - 2²·(y + 3)²/6² = 1
(x - 2)²/2² - (y + 3)²/3² = 1
The equation of the hyperbola is (x - 2)²/2² - (y + 3)²/3² = 1.
The coordinates that you record is an example of data from the graph I think
Answer:
what can i help u with
Step-by-step explanation:
The graph of x = |y| is as shown in the figure.
When we draw a vertical line, it intersects the graph at two points.
This means for the same value of x , we have two values of y.
Or in other words, for the same pre image, we have two images.
Hence it is not a function.
But for every value of x, we do have a value of y, hence it is a relation.
x = |y| is a relation but it is not a function
This would follow the
format
where m would be the price per cup
and b would be the money you start off with
y = A
and x = j
so we get
A = 0.75j + 14
as your answer
