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cestrela7 [59]
3 years ago
11

Javier asks his mother how old a tree in their yard is. His mother says, “The sum of 10 and two-thirds of that tree’s age, in ye

ars, is equal to 50.” 
Javier writes the equation , where a is the tree’s age in years. His equation is not correct. What error did he make? ​
Mathematics
1 answer:
sdas [7]3 years ago
5 0

Answer:

10 + (\frac{2}{3}) a = 50 is the CORRECT equation.

Step-by-step explanation:

The given question is INCOMPLETE.

Javier asks his mother how old a tree in their yard is. His mother says, “The sum of 10 and two-thirds of that tree’s age, in years, is equal to 50.” Javier writes the equation { 10 + 2/3} where a is the tree’s age in years. His equation is not correct. What error did he make?

Now here:

a:  The tree’s age in years.

Also,  “The sum of 10 and two-thirds of that tree’s age, in years, is equal to 50.”

⇒ 10 +  two-thirds of that tree’s age  = 50

\implies 10 + (\frac{2}{3}) a = 50

But in the equation written by Javier, the the third fraction is NOT MULTIPLIED by the age of the tree a in Years.

So, the written equation by Javier is Incorrect.

Now, solving the written correct equation for the value of a, we get:

\implies 10 + (\frac{2}{3}) a = 50\\\implies  (\frac{2}{3}) a = 40\\\implies a = 40 \times  (\frac{3}{2})  = 60\\\implies a  = 60

Hence the correct  age of the tree = 60 years

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-3x - y = -17
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multiply one part of the equation so that we can be able to use the process of elimination.

(-3x - y = -17)2
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Now we have:

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------------------------
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Divide -2 on both sides.

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=============================================

To solve for y, we just have to substitute the value of x to any of the equation given above, that we feel comfortable with. And I'm going to choose this equation: 4x + 2y = 20


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---------------------
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The last thing you would do is to check if the answers is correct.
All you have to do is plug in the values of x and y into both equations and see if they equal to one another.

You may have to do this by yourself :P

Anyways, if you have any questions about this topic, feel free to PM me or any other users interested. Thank you for being part of Brainly! Have a nice day!










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