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3 years ago

Value of 8 power of -3

Mathematics

1 answer:

lozanna [386]3 years ago

7 0

Answer:

Step-by-step explanation: $8^{-3} =\frac{1}{8^{3} } =\frac{1}{8X8X8} =\frac{1}{512}$

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Look at the following numbers: −5, −6, 0, 6 Which pair of numbers has a sum of zero? −6, 0 −5, 6 6, −6 −5, 0

galben [10]

Answer:

6, -6

Step-by-step explanation:

If you have 6, and add -6, you get 0. :)

6 0

3 years ago

Read 2 more answers

What is the length of the third side of the window frame ??

drek231 [11]

A^2+b^2=c^2
A=63
B=?
C=87
63^2+b^2=87^2
3969+b^2=7569
-3969 both sides
B^2=3600
Square root both sides
B=60in

5 0

2 years ago

Read 2 more answers

Carlos earns $11 per hour at his job. Let x represent the number of hours he worked in May. Let y represent the number of hours

Firlakuza [10]

11x+11y

11(x+y)

Explanation

Step 1

Let

Carlos earns == 11 per hour

x represents the number of hours he worked in May

the,

the amount he earned in Mayis

$11\cdot x=11x$

y represent the number of hours he worked in June.

the amount he earned in June was

$11\cdot y=11y$

Step 2

the amount of money he earned is May and June is the sum of the values

$\begin{gathered} \text{total}= \\ 11x+11y \\ \text{if we factorize 11} \\ 11(x+y) \end{gathered}$

I hope this helps you

5 0

10 months ago

Help ASAP show work please thanksss!!!!

Llana [10]

Answer:

$\displaystyle log_\frac{1}{2}(64)=-6$

Step-by-step explanation:

<u>Properties of Logarithms</u>

We'll recall below the basic properties of logarithms:

$log_b(1) = 0$

Logarithm of the base:

$log_b(b) = 1$

Product rule:

$log_b(xy) = log_b(x) + log_b(y)$

Division rule:

$\displaystyle log_b(\frac{x}{y}) = log_b(x) - log_b(y)$

Power rule:

$log_b(x^n) = n\cdot log_b(x)$

Change of base:

$\displaystyle log_b(x) = \frac{ log_a(x)}{log_a(b)}$

Simplifying logarithms often requires the application of one or more of the above properties.

Simplify

$\displaystyle log_\frac{1}{2}(64)$

Factoring $64=2^6$ .

$\displaystyle log_\frac{1}{2}(64)=\displaystyle log_\frac{1}{2}(2^6)$

Applying the power rule:

$\displaystyle log_\frac{1}{2}(64)=6\cdot log_\frac{1}{2}(2)$

Since

$\displaystyle 2=(1/2)^{-1}$

$\displaystyle log_\frac{1}{2}(64)=6\cdot log_\frac{1}{2}((1/2)^{-1})$

Applying the power rule:

$\displaystyle log_\frac{1}{2}(64)=-6\cdot log_\frac{1}{2}(\frac{1}{2})$

Applying the logarithm of the base:

$\mathbf{\displaystyle log_\frac{1}{2}(64)=-6}$

5 0

2 years ago

What is the slope of the line that passes through the points (-4, 0) and (-4, -10)? Write your answer in simplest form.

Tresset [83]

Answer:

<h2> There is no slope.</h2>

Step-by-step explanation:

$slope=\dfrac{y_2-y_1}{x_2-x_1}$

It means that for a line passing through two points to have the slope, the x-coordinates of these point have to be different.

(-4, 0) and (-4, -10) means x₁ = x₂ = -4, <u>so there is no slope.</u>

{the line is parallel to Y-axis, and has an equation: x=-4}

4 0

3 years ago