Answer:
the length of the rope gives the circumference of the tree trunk. the tree trunk is in the shape of a circle. the circumference of a circle = πD. the inches would be converted to foot and the diameter would be determined from the length of the rope.
7 foot
Step-by-step explanation:
Here is the full question :
A group of students wants to find the diameter of the trunk of a young sequoia tree. The students wrap a rope around the tree trunk. the length is 21 feet 8 inches
Explain how they can use the length to determine the diameter of the tree trunk to the nearest half foot
What is the diameter of the tree trunk
the circumference of a circle = πD
π = 22/ 7
D = diameter
we need to convert 21 feet 8 inches to foot
1 inch = 0.0833333 foot
8 x 0.0833333 = 0.667
0.667 + 21 = 21.667 foot
21.667 = 22/7 x diameter
diameter = 21.667 x 7/22 = 6.89 foot
The nearest half foot of 6.89 is 7.
7 foot
Answer:
number of $20 bill = 4
Number of $5 bill = 5
Step-by-step explanation:
Given that:
Total number of $5 and $20 bills = 9
Let :
Number of $5 bills = x
Number of $20 bills = y
Combined worth of all bills = $105
x + y = 9 - - - (1)
5x + 20y = 105 - - - (2)
From (1)
x = 9 - y
Substitute x = 9 - y into (2)
5(9 - y) + 20y = 105
45 - 5y + 20y = 105
15y = 105 - 45
15y = 60
y = 60/15
y = 4
x = 9 - y
x = 9 - 4 = 5
Hence,
number of $20 bill = 4
Number of $5 bill = 5
Answer:
y = -3x -2.5
slope: -3
y-intercept: -2.5
Step-by-step explanation:
Solve for y.
-4y = 12x + 10 . . . . . add 12x to get the y-term by itself
y = -3x -2.5 . . . . . . .divide by the coefficient of y
__
The slope is the coefficient of x, -3.
The y-intercept is the constant, -2.5.
☁️ Answer ☁️
4x^2 - 12x + 5
(Pls report my answer)
Hope it helps.
Have a nice day noona/hyung.
We are given area of the spherical lampshade = 57.76 \pi square inches.
We know formula of area of a spherical shape:
Plugging area A= 57.76 π in formula, we get
Dividing both sides by 4π, we get
Taking square root on both sides, we get
r =3.8.
<h3>Therefore, the radius of the lampshade is 3.8 inches.</h3>
