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icang [17]
3 years ago
14

What is the value of ( 0.4) ^3

Mathematics
1 answer:
cestrela7 [59]3 years ago
8 0

Answer:

0.064

Step-by-step explanation:

( 0.4) ^3

Solution :

( 0.4) ^3

= 0.4 x 0.4 x 0.4

= 0.064

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Please give me the answer please
In-s [12.5K]
If there are 4 trucks then the first truck weighs x
then x+2tons
then x+4tons
then x+6tons = 32tons
so 4x+12=32
         -12   -12
     /4         /4
x=5 
so plug it back in 
truck 1= 5tons or 10,000lbs
truck 2= 7tons or 14,000lbs
truck 3= 9tons or 18,000lbs
truck 4= 11tons or 22,000lbs

5 0
3 years ago
If PQR is an equilateral triangle, PQ=18x+1, QR=24x-17, and PR=15x+10, find x and the measure of each side.
Vadim26 [7]

Answer

QR= PQ= PR

18x+1= 24x-17

18x-24x= -17-1

-6x= -18

x= 3

QR= 24(3)-17= 55

PQ= 18(3)+1= 55

PR= 15(3)+10=55

8 0
3 years ago
Read 2 more answers
There are 12 red marbles and 8 green marbles in a bag. What is the probability of selecting a red
madam [21]

Answer:

The probability of selecting a red  marble, not replacing it, and then selecting a green marble from the bag is 24/95

Step-by-step explanation:

Number of red marbles = 12

Number of green marbles = 8

Total number of marbles = 12+8 = 20

Probability of selecting red marble =\frac{12}{20}

Since it is the case of no replacement

Remaining marbles = 20-1 = 19

Number of red marbles = 12-1=11

Number of green marbles = 8

Probability of selecting green marble =\frac{8}{19}

So, the probability of selecting a red  marble, not replacing it, and then selecting a green marble from the bag =\frac{12}{20} \times \frac{8}{19}=\frac{24}{95}

Hence the probability of selecting a red  marble, not replacing it, and then selecting a green marble from the bag is 24/95

3 0
4 years ago
Need help on this one!! plz show process
diamong [38]
Sally is 6 and Tomas is 3 so

6 +(3×2)

and 6-3
6 0
3 years ago
Find solution to the system of linear equations. 5x1 + x2 = 0 , 25x1 + 5x2 = 0
Zigmanuir [339]

Answer:

the system of equation has infinite solution

Step-by-step explanation:

5x_1 + x_2 = 0 , 25x_1 + 5x_2 = 0

Solve the first equation for x_2

Subtract 5x1 on both sides

5x_1 + x_2 = 0

x_2 =-5x_1

Now substitute -5x1 on second equation

25x_1 + 5x_2 = 0

25x_1 + 5(-5x_1)= 0

25x_1-25x_1= 0

0=0

So the system of equation has infinite solution

5 0
3 years ago
Read 2 more answers
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