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Temka [501]
4 years ago
13

Multiply. Write your answer in simplest form. 2 1/2 x 3 2/3

Mathematics
2 answers:
oksian1 [2.3K]4 years ago
7 0
2 \frac{1}{2}  *  3 \frac{2}{3}  =   \frac{5}{2}  *   \frac{11}{3}
                    =  \frac{55}{6}
                    =  9 \frac{1}{6}

yKpoI14uk [10]4 years ago
7 0

Answer:

9^1/6

Step-by-step explanation:

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A comic-strip writer churns out a different number of comic strips each day. For 16 days, the writer logged the number of comic
Rudik [331]
One way to observe the skewness of a data set is to find the quartiles: Q₁, Q₂, Q₃ and then sketch the box plot

We have the data set already in ascending order, so finding the quartiles is quite straight forward. 

We have Q₁ = 2, Q₂ = 3, Q₃ = 5 (refer to the first picture below)

The box plot is given in the second picture and from this plot, we can see that the data tail slightly on the right, and this shows a positive skew.

8 0
4 years ago
( 4a + 1 )( 7a 2 - 3a - 5 ) simplified
enot [183]

Answer:

28a³ - 5a² - 23a - 5

Step-by-step explanation:

FOIL and Distribute Parenthesis

Step 1: Write out expression

(4a + 1)(7a² - 3a - 5)

Step 2: Distribute 4a

28a³ - 12a² - 20a

Step 3: Distribute 1

7a² - 3a - 5

Step 4: Combine

28a³ - 12a² - 20a + 7a² - 3a - 5

Step 5: Combine like terms

28a³ - 5a² - 23a - 5

3 0
3 years ago
If 2000 is placed into a bank that pays 3% compound per year how much will be in the acoount after 2 years
avanturin [10]

Answer: Total $2,063.10


8 0
3 years ago
To test if the mean IQ of employees in an organization is greater than 100, a sample of 30 employees is taken and the value of t
ivolga24 [154]

Answer:

p_v =P(t_{(29)}>1.42)=0.0831  

For this case the p value calculated is higher than the significance level used of 0.05 so then we have enough evidence to FAIL to reject the null hypothesis and the best conclusion for this case would be:

a) do not reject the null hypothesis and conclude that the mean IQ is not greater than 100

Step-by-step explanation:

Information given

We want to verify if he mean IQ of employees in an organization is greater than 100 , the system of hypothesis would be:  

Null hypothesis:\mu \leq 100  

Alternative hypothesis:\mu > 100  

The statistic for this case is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

The statistic calculated for this case  t_{calc}= 1.42

The degrees of freedom are given by:

df=n-1=30-1=29  

Now we can find the p value using tha laternative hypothesis and we got:

p_v =P(t_{(29)}>1.42)=0.0831  

For this case the p value calculated is higher than the significance level used of 0.05 so then we have enough evidence to FAIL to reject the null hypothesis and the best conclusion for this case would be:

a) do not reject the null hypothesis and conclude that the mean IQ is not greater than 100

5 0
4 years ago
Pls help I'll mark brainliest
r-ruslan [8.4K]

Answer:

blue

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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