X=3.5 add 10 and divide by 8
The best option is C. 0.0823mean = np = 48*1/4 = 12
SD = sqrt(npq) = sqrt(48 *1/4 *3/4) = 3
aplying continuity correction for using a continuous distribution for a discrete one,
"exactly 15" means 14.5 to 15.5
z1= (14.5-12)/3 = 0.833 , z2 = (15.5-12)/3 = 1.167
P(0.833 < z < 1.167) = 0.0808
Answer:
Each Tomskian build 6 igloos per week.
Each Kyzylian build 5 igloos per week.
Step-by-step explanation:
Let T represent the number of Tomskians and K represent the number of Kyzylians the company needs to employ to meet its goal.
The inequality:
represents the situation that a company plans to build at least 152 igloos in a single week by employing T Tomskians and K Kyzylians.
We can see that 6T represents the number of igloos made by T Tomskians in one week and 5K represents the number of igloos made by K Kyzylians in one week .
Since all Tomskians and Kyzylians build the same number of igloos per week, therefore, each Tomskian build 6 igloos per week and each Kyzylian build 5 igloos per week.
1 and 16, 2 and 8, 4 and 4.
3y = 18 |divide both sides by 3
y = 6