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sukhopar [10]
3 years ago
6

A portion is represented by

Mathematics
1 answer:
Mumz [18]3 years ago
8 0

Answer:

d

Step-by-step explanation:

i dont know it just be like that

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<img src="https://tex.z-dn.net/?f=x%20%5Cdiv%202%20%2B%20x%20%5Cdiv%203%20%3D%201%20" id="TexFormula1" title="x \div 2 + x \div
blsea [12.9K]

Answer:

Exact form : x=6/5

Decimal form : x=1.2

Mixed Number form : x=1 1/5

Step-by-step explanation: Solve for x by simplifying both sides of he equation, then isolating the variable.

Hope this helps you out! ☺

4 0
3 years ago
What must be true for lines a and b to be parallel lines? Check all that apply
iren [92.7K]

the question does not present the options, but this does not interfere with the resolution


we know that

if a and b are parallel lines

so


1) m∠2=58°------> by corresponding angles


2) m∠1=4x-10------> by alternate exterior angles


3) [m∠2+m∠(3x-1)]+m ∠1=180°------> by supplementary angles

58+(3x-1)+4x-10=180

7x=180-47

7x=133

x=19°


4) angle (4x-10)=-4*19-10-------> 66°


5) angle 3x-1=3*19-1-------> 56°

3 0
3 years ago
Given the graph below write the equation of the line.
Scrat [10]

Answer:

y = 2x+8

Step-by-Step Explanation:

The equation should be in the form of y=mx+b

So you already know it's not A. Also you already know it's not D because the line goes at an angle, if "m"(slope) was 0 then the line would be straight horizontal or straight vertical. So that leaves B and C. And finally you know it's not B because the line is going in the positive direction not negative, so the slope has to be positive, also "b" in the equation is the y-intercept, and that's where the line intersects with the y-axis, and you can see that the line intersects at 8 on the graph. Therefore, the answer is C, y=2x+8

Hope this helps!! :)

4 0
2 years ago
Read 2 more answers
What is the answer to this question? Write an expression in simplest form for the perimeter of a right triangle with leg lengths
blagie [28]

Answer:

Step-by-step explanation:

Since the length of both legs of the right angle triangle are given, we would determine the hypotenuse, h by applying Pythagoras theorem which is expressed as

Hypotenuse² = one leg² + other leg²

Therefore,

h² = (3a)³ + (4a)³

h² = 27a³ + 64a³

h² = 91a³

Taking square root of both sides,

h = √91a³

The formula for determining the perimeter of a triangle is expressed as

Perimeter = a + b + c

a, b and c are the side length of the triangle. Therefore, the expression for the perimeter of the right angle triangle is

√91a³ + (3a)³ + (4a)³

= √91a³ + 91a³

7 0
2 years ago
Please help and show all work so I can fully understand it, thanks.
seraphim [82]

Answer:

\frac{1}{m-4}

Step-by-step explanation:

\frac{\frac{4m-5}{m^4 -7m^3 +12m^2}}{\frac{4m-5}{m^3 -3m^2}}

Factor the equation:

\frac{\frac{4m-5}{m^2(m^2 -7m+12)}}{\frac{4m-5}{m^2(m-3)}}

\frac{\frac{4m-5}{m^2(m-3)(m-4)}}{\frac{4m-5}{m^2(m-3)}}

Rewrite to suit the format of multiplying two fractions. Remember, dividing two fractions is the same as multiplying the first fraction by the reciprocal of the second. A reciprocal of a fraction is when one switches the place of the numerator and the denominator, that is, the value on top (numerator), and the value on the bottom (denominator).

\frac{4m-5}{m^2(m-3)(m-4)}*\frac{m^2(m-3)}{4m-5}

Simplify, take out common terms that are found on both the numerator and denominator

\frac{4m-5}{m^2(m-3)(m-4)}*\frac{m^2(m-3)}{4m-5}

\frac{1}{m-4}

4 0
3 years ago
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