3/11+8/21+5/22+1/63+7/24+3/8

Can someone please help I can't solve this problem!!!!!!!!!!!

notsponge [240]

Answer:

8 dolls

Step-by-step explanation:

METHOD 1:

Step 1: Convert 25% into decimal (0.25)

Step 2: Multiply by 32 (32 × 0.25 = 8)

METHOD 2:

25% of a number will be one-fourth of that number. Divide 32 by 4 to get 8 (or multiply 32 by 1/4).

6 0

2 years ago

What is the following product?

VMariaS [17]

For this case we must find the product of the following expression:

$\sqrt {12} * \sqrt {18}$

We combine using the product rule for radicals:

$\sqrt [n] {a} * \sqrt [n] {b} = \sqrt [n] {ab}$

So, we have:

$\sqrt {12 * 18} =\\\sqrt {216} =$

We rewrite the 216 as $6 * 6 * 6 = 6 ^ 3 = 6 ^ 2 * 6$

$\sqrt {6 ^ 2 * 6} =$

By definition of properties of powers and roots we have:

$\sqrt [n] {a ^ n} = a ^ {\frac {n} {n}} = a$

Then, the expression is:

$6 \sqrt {6}$

Answer:

Option D

6 0

2 years ago

Read 2 more answers

The distribution of resistance for resistors of a certain type is known to be normal, with 10% of all resistors having a resista

baherus [9]

Answer:

The mean is 9.65 ohms and the standard deviation is 0.2742 ohms.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

10% of all resistors having a resistance exceeding 10.634 ohms

This means that when X = 10.634, Z has a pvalue of 1-0.1 = 0.9. So when X = 10.634, Z = 1.28.

$Z = \frac{X - \mu}{\sigma}$

$1.28 = \frac{10.634 - \mu}{\sigma}$

$10.634 - \mu = 1.28\sigma$

$\mu = 10.634 - 1.28\sigma$

5% having a resistance smaller than 9.7565 ohms.

This means that when X = 9.7565, Z has a pvalue of 0.05. So when X = 9.7565, Z = -1.96.

$Z = \frac{X - \mu}{\sigma}$

$-1.96 = \frac{9.7565 - \mu}{\sigma}$

$9.7565 - \mu = -1.96\sigma$

$\mu = 9.7565 + 1.96\sigma$

We also have that:

$\mu = 10.634 - 1.28\sigma$

So

$10.634 - 1.28\sigma = 9.7565 + 1.96\sigma$

$1.96\sigma + 1.28\sigma = 10.645 - 9.7565$

$3.24\sigma = 0.8885$

$\sigma = \frac{0.8885}{3.24}$

$\sigma = 0.2742$

The mean is

$\mu = 10.634 - 1.28\sigma = 10 - 1.28*0.2742 = 9.65$

The mean is 9.65 ohms and the standard deviation is 0.2742 ohms.

8 0

3 years ago

Alan mixes 1 1/3 cups of milk with a can of condensed soup. He makes a total of 2 5/8 cups of soup. How many cups of condensed s

Sonja [21]

To find the amount of soup in the soup-milk mixture, we just need to subtract the amount of milk from the amount of soup-milk mixture.

2 5/8 - 1 1/3 = 1 7/24.

There were 1 7/24 cups of soup in the can.
Hope that helped =)

8 0

3 years ago

Two small fires are spotted by a ranger from a fire tower 60 feet above ground. The angles of depressions re 11.6° and 9.4°. How

Hitman42 [59]

<span>The two fires are about 70 feet from each other. The assumption is that the ground is relatively level and that a right triangle will be made with the three points of the triangle being the ranger, the spot on the ground directly beneath the ranger, and the fire itself. So the distance to the first fire will be: Calculate the angle. That will be 90° - 11.6° = 78.4° The distance will be tan(78.4) = X/60 60 tan(78.4) = X 60 * 4.871620136 = X 292.2972082 = X And that's how far the 1st fire is from the ranger's station. Now for the 2nd angle = 90° - 9.4° = 80.6° 60 tan(80.6) = X 60 * 6.040510327 = X 362.4306196 = X And the distance between the two fires will be the difference in distance from the tower, so 362.4306196 - 292.2972082 = 70.13341146 Rounding to 2 significant figures gives 70 feet.</span>

4 0

3 years ago