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3 years ago

What is the first quartile of this data set? {6, 47, 49, 15, 43, 41, 7, 36}

1 answer:

5 0

<span>The first quartile is the same as the median of the data which are less than the overall median. Same as the 25th percentile.
</span>
I hope my answer has come to your help. God bless and have a nice day ahead!

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4/5(p+1)=1 wgat equals p

jeka94

Answer:

p= 1/4 or 0.25

Step-by-step explanation:

4 0

3 years ago

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I need help to evaluate the function for the given value of x for y=2×5x; x=2

mars1129 [50]

Answer:

y= 20

Step-by-step explanation:

y=2*5x

Let x =2

y = 2*5 (2)

y = 10*2

y= 20

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3 years ago

A student desk measures 1.5 meters. The dry erase board measures 3.5 meters. How much longer is the dry erase board than the des

Serga [27]

The dry erase board is 200 centimeters longer.

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3 years ago

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Sviatoslav solved the quadratic equation x^2-x-1=0 by completing the square. In the process, he came up with the equivalent equa

zimovet [89]

Answer:

$x=\frac{1+\sqrt5}{2}$ and $x=\frac{1-\sqrt5}{2}$

and b= $\frac{5}{4}$

Step-by-step explanation:

We are given that a quadratic equation

$x^2-x-1=0$

We have to solve the equation by completing square and find the value of b.

$(x)^2-2\times x\times \frac{1}{2}+(\frac{1}{2})^2-(\frac{1}{2})^2-1=0$

$(x-\frac{1}{2})^2-\frac{1}{4}-1=0$

$(x-\frac{1}{2})^2-\frac{1-4}{4}=0$

$(x-\frac{1}{2})-\frac{5}{4}=0$

$(x-\frac{1}{2})^2-(\frac{\sqrt5}{2})^2=0$

$(x-\frac{1}{2})^2=(\frac{\sqrt5}{2})^2$

$x-\frac{1}{2}=\frac{\sqrt5}{2}$ and $x-\frac{1}{2}=-\frac{\sqrt5}{2}$

$x=\frac{\sqrt5}{2}+\frac{1}{2}=\frac{1+\sqrt5}{2}$

And $x=\frac{1}{2}-\frac{\sqrt5}{2}=\frac{1-\sqrt5}{2}$

Therefore, $x=\frac{1+\sqrt5}{2}$ and $x=\frac{1-\sqrt5}{2}$

and b= $\frac{5}{4}$

6 0

3 years ago

Whats the area and perimeter to the shape below?

Anarel [89]

Answer:

Step-by-step explanation:

a) Area of white square = side *side = 8 * 8 = 64 sq.mm

Area of 4 white square = 4 * 64 = 256 sq.mm

compound shape

length = 3 cm = 30 mm

Width = 2 cm = 20 mm

Area of compound shape = length *width = 30 * 20 = 600 sq.mm

Area of the shaded part of the compound shape =

Area of compound shape - Area of 4 white square

= 600 - 256

= 344 sq.mm

b) Perimeter of compound shape = 2*(length + width)

= 2*(30 +20)

= 2* 50

= 100 mm

6 0

3 years ago