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algol [13]
3 years ago
14

Which inequality is represented by this graph?​

Mathematics
1 answer:
STatiana [176]3 years ago
6 0

Answer:

Two-variable inequalities from their graphs (video)

Step-by-step explanation:

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If DE=3x+7, EF=2x-3 and DF=7x-9, find DF
Lunna [17]

Answer:

So -63 isn't the right answer. It is either 6.5 or 13/2 based on how your teacher wants the answer.

Step-by-step explanation:

I did the work to show you how i got there. It is definitely not -63. I hope this helps!

5 0
3 years ago
How to find the slope of the equation is y= 16,500 - 1,500x
kakasveta [241]
Well by looking at the equation I would say it already tells you the slope. The slope would be -1,500x.
It would be set up like, y=-1,500x+16,500
Hope that helps! (:
4 0
4 years ago
Does there exist a di↵erentiable function g : [0, 1] R such that g'(x) = f(x) for all x 2 [0, 1]? Justify your answer
agasfer [191]

Answer:

No; Because g'(0) ≠ g'(1), i.e. 0≠2, then this function is not differentiable for g:[0,1]→R

Step-by-step explanation:

Assuming:  the function is f(x)=x^{2} in [0,1]

And rewriting it for the sake of clarity:

Does there exist a differentiable function g : [0, 1] →R such that g'(x) = f(x) for all g(x)=x² ∈ [0, 1]? Justify your answer

1) A function is considered to be differentiable if, and only if  both derivatives (right and left ones) do exist and have the same value. In this case, for the Domain [0,1]:

g'(0)=g'(1)

2) Examining it, the Domain for this set is smaller than the Real Set, since it is [0,1]

The limit to the left

g(x)=x^{2}\\g'(x)=2x\\ g'(0)=2(0) \Rightarrow g'(0)=0

g(x)=x^{2}\\g'(x)=2x\\ g'(1)=2(1) \Rightarrow g'(1)=2

g'(x)=f(x) then g'(0)=f(0) and g'(1)=f(1)

3) Since g'(0) ≠ g'(1), i.e. 0≠2, then this function is not differentiable for g:[0,1]→R

Because this is the same as to calculate the limit from the left and right side, of g(x).

f'(c)=\lim_{x\rightarrow c}\left [\frac{f(b)-f(a)}{b-a} \right ]\\\\g'(0)=\lim_{x\rightarrow 0}\left [\frac{g(b)-g(a)}{b-a} \right ]\\\\g'(1)=\lim_{x\rightarrow 1}\left [\frac{g(b)-g(a)}{b-a} \right ]

This is what the Bilateral Theorem says:

\lim_{x\rightarrow c^{-}}f(x)=L\Leftrightarrow \lim_{x\rightarrow c^{+}}f(x)=L\:and\:\lim_{x\rightarrow c^{-}}f(x)=L

4 0
4 years ago
My first is in shape and also in space;
vova2212 [387]

Answer:

360

Step-by-step explanation:

this took so long

please be easy on me if i am wrong....i spent 30 minutes of my life on this for you guys

6 0
3 years ago
Im dying plz helpppppp
Korvikt [17]

Answer:

A and B

Step-by-step explanation:

5 0
3 years ago
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