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3 years ago

The average adult breathes in about 37L of air every 5 minutes. What is the rate of change of volume of air ?

Mathematics

1 answer:

galben [10]3 years ago

8 0

37L/5 min. = 7.4 L/min.

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How do I solve this problem?

geniusboy [140]

Answer:

i think is 7/12

because if 4/7 chose pasta,1/5 chose pizza then we add 7+5=12 then we sudstract 12-4-1 = 7.

hope that helps

4 0

2 years ago

Luke mowed a lawn today to earn some extra money. He spent $2.10 on fuel and $4.45 on lunch. He charged $13.50 to mow the lawn.

liberstina [14]

If you add his expenses, $2.10 + $4.45 you’ll get that Luke spent $6.55 today.

Then subtract his expenses by how much he made for mowing the lawn, $13.50 - $6.55 =

Your answer is A. $6.95

8 0

4 years ago

Read 2 more answers

I need help with this ASAP!!!

SVETLANKA909090 [29]

Answer:

Step-by-step explanation:

12.5= 25/2

Ln (25/2).. change decimal to fraction

Ln ((5^2)/2)...change 25 to 5^2

(2ln 5)/2... log rule.. move exponent to the front

Ln 5 .. . Simplify the top and bottom 2's

3 0

3 years ago

Can anyone help me!

zhenek [66]

Answer:

$\large \text{$ \sf 2^{-64}$}$

Step-by-step explanation:

Given:

$\large \text{$ \sf (256)^{-4^{\frac{3}{2}}}$}$

This reads as: 256 to the power of "-4 to the power of 3/2".

Therefore, we need to deal with the "-4 to the power of 3/2" first.

Rewrite the 4 as 2²:

$\large \text{$ \sf \implies -(2^2)^{\frac{3}{2}}$}$

$\textsf{Apply exponent rule} \quad (a^b)^c=a^{bc}:$

$\large \text{$ \sf \implies -2^{\left(2 \times \frac{3}{2}\right)}$}$

$\large \text{$ \sf \implies -2^{3}$}$

Therefore:

$\large \text{$ \sf \implies -2^3=(-2)(-2)(-2) = -8$}$

Replace "-4 to the power of 3/2" with -8 :

$\large \text{$ \sf \implies 256^{-8}$}$

Rewrite 256 as 2⁸ :

$\large \text{$ \sf \implies (2^8)^{-8}$}$

$\textsf{Again, apply exponent rule} \quad (a^b)^c=a^{bc}:$

$\large \text{$ \sf \implies 2^{(8 \times -8)}$}$

$\large \text{$ \sf \implies 2^{-64}$}$

In one complete calculation:

$\large\begin{aligned} \sf (256)^{-4^{\frac{3}{2}}} & = \sf (256)^{-(2^2)^{\frac{3}{2}}}\\& = \sf (256)^{-2^{\left(2 \times \frac{3}{2}\right)}}\\& =\sf (256)^{-2^{3}}\\& = \sf (256)^{-8}\\& \sf = (2^8)^{-8}\\& = \sf 2^{(8 \times -8)}\\& =\sf 2^{-64}\end{aligned}$