Simplify. Y/3 + 1/y^2/9

Someone plz help fast will give brainiest

Georgia [21]

Answer:

$5

Step-by-step explanation:

The bill was $15 extra this month so 15 divided by 3 is 5.

4 0

4 years ago

Find the probability of two persons being born on the same day?

Vinil7 [7]

Answer:

1/365

Step-by-step explanation:

The probability of being born any day of the year is 1 or more specifically: 365/365. Since Person B must be born on the same day as Person A their probability is 1/365

3 0

3 years ago

Read 2 more answers

A small regional carrier accepted 21 reservations for a particular flight with 19 seats. 10 reservations went to regular custome

Viefleur [7K]

We have 19 available seats, and 21 reservations.

Of the 21 reservations, 10 are sure, so we have 10 out of the 19 seats that are surely occupied.

Then, we have 9 seats for 11 reservations, each one with 44% chance of being occupied.

We have to calculate the probability that the plane is overbooked. This means that more than 9 of the reservations arrive.

This can be modelled as a binomial distirbution with n = 11 and p = 0.44, representing the 44% chance.

Then, we have to calculate P(x > 9).

This can be calculated as:

$P(x>9)=P(x=10)+P(x=11)$

and each of the terms can be calculated as:

$\begin{gathered} P(x=10)=\dbinom{11}{10}\cdot0.44^{10}\cdot0.56^1=11\cdot0.0003\cdot0.56=0.0017 \\ P(x=11)=\dbinom{11}{11}\cdot0.44^{11}\cdot0.56^0=1\cdot0.0001\cdot1=0.0001 \end{gathered}$

Then:

$P(x>9)=P(x=10)+P(x=11)=0.0017+0.0001=0.0018$

We have a probability of 0.18% of being overbooked (P = 0.0018).

If we want to calculate the probability of having empty seats, we need to calculate P(x<9), meaning that less than 9 of the reservations arrive.

We can express this as:

$P(x$

We have to calculate P(x=9) as we already have calculated the other two terms:

$P(x=9)=\dbinom{11}{9}\cdot0.44^9\cdot0.56^2=55\cdot0.0006\cdot0.3136=0.0107$

Finally, we can calculate:

$\begin{gathered} P(x$

There is a probability of 0.9875 that there is one or more empty seats.

Answer:

There is a probability of 0.0018 of being overbooked.

There is a probability of 0.9875 of having at least one empty seat.

7 0

1 year ago

-5/6 - 17/18 - (-2/9)

Sunny_sXe [5.5K]

First, let's fine the decimal of each fraction.

-5 Divided By 6 = -0.83333333333

17 Divided By 18 = 0.94444444444

-2 Divided By 9 = -0.22222222222

-5/6 - 17/18 - (-2/9) = -1.55555555556

8 0

3 years ago

A student takes a multiple-choice test that has 11 questions. Each question has five choices. The student guesses randomly at ea

marissa [1.9K]

Answer:

a) P(6) = 0.0097

b) P(More than 3) = 0.1611

Step-by-step explanation:

For each question, there are only two possible outcomes. Either it is guessed correctly, or it is not. Questions are independent of each other. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$