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Blizzard [7]
3 years ago
8

Guys I need help pleeeaassee i'm trying to graduate! Find the area of the shaded portion in the square. (assuming the central po

int of each arc is the corresponding corner)

Mathematics
1 answer:
Licemer1 [7]3 years ago
6 0
Area of the square = (side)*(side)
Area of the square = (2)*(2)
Area of the square = 4 

Area of the quarter circle = (area of full circle)/4
Area of the quarter circle = (pi*r^2)/4
Area of the quarter circle = (pi*1^2)/4
Area of the quarter circle = (1/4)*pi

The top shaded region is found by taking the area of the square and subtracting off the area of the quarter circle, so we get,

top shaded region area = (area of square) - (area of quarter circle)
top shaded region area = (4) - (1/4pi)

The two shaded regions are congruent so we can double the area of the top region to get the total overall area. 

Total shaded area = 2*(top shaded region area)
Total shaded area = 2*(4 - pi/4)
Total shaded area = 8 - pi/2
Total shaded area = 8 - (1/2)pi

Therefore, the final answer is 8 -  \frac{1}{2}\pi

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Answer:

n = \frac{4}{3}c

c:0\ \ \ \frac{3}{4}\ \ \ \frac{3}{2}\ \ \ \frac{9}{4}\ \ \ 3\ \ \ 3\frac{3}{4}\\n:0\ \ \ \ 1\ \ \ 2\ \ \ 3\ \ \ \ 4\ \ \ \ 5

Step-by-step explanation:

Given

See attachment for complete question

Required

Complete the double number line

The given double number lines represent a linear function between cups of flour (c) and number of batched (n)

Pick any two pairs:

(c_1,n_1) = (\frac{3}{4},1)

(c_2,n_2) = (3\frac{3}{4},5)

First, calculate the rate of change (i.e. slope, m):

m = \frac{n_2 - n_1}{c_2 - c_1}

m = \frac{5-1}{3\frac{3}{4} - \frac{3}{4}}

m = \frac{4}{3}

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n = m(c - c_1) + n_1

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n = \frac{4}{3}(c - \frac{3}{4}) + 1

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<u>To complete the table</u>

When n = 2

Substitute n = 2 in: n = \frac{4}{3}c

2 = \frac{4}{3}c

Make c the subject

c = \frac{3*2}{4}

c = \frac{3}{2}

When n = 3

Substitute n = 3 in: n = \frac{4}{3}c

3 = \frac{4}{3} * c

Make c the subject

c = \frac{3*3}{4}

c = \frac{9}{4}

When c=3

Substitute c=3 in: n = \frac{4}{3}c

n = \frac{4}{3} * 3

n = 4

So, the complete table is:

c:0\ \ \ \frac{3}{4}\ \ \ \frac{3}{2}\ \ \ \frac{9}{4}\ \ \ 3\ \ \ 3\frac{3}{4}\\n:0\ \ \ \ 1\ \ \ 2\ \ \ 3\ \ \ \ 4\ \ \ \ 5

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Answer:

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<em></em>

Step-by-step explanation:

Given

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To solve this question, we make use of trial by error method by taking the options one at a time:

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<em />

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