I don’t know but if I did I’m sur it would be helpful sorry though
Answer:
y(t) = c₁ e^(-1/2 t) cos(√3/2 t) + c₂ e^(-1/2 t) sin(√3/2 t) + 1
Step-by-step explanation:
y" + y' + y = 1
This is a second order nonhomogenous differential equation with constant coefficients.
First, find the roots of the complementary solution.
y" + y' + y = 0
r² + r + 1 = 0
r = [ -1 ± √(1² − 4(1)(1)) ] / 2(1)
r = [ -1 ± √(1 − 4) ] / 2
r = -1/2 ± i√3/2
These roots are complex, so the complementary solution is:
y = c₁ e^(-1/2 t) cos(√3/2 t) + c₂ e^(-1/2 t) sin(√3/2 t)
Next, assume the particular solution has the form of the right hand side of the differential equation. In this case, a constant.
y = c
Plug this into the differential equation and use undetermined coefficients to solve:
y" + y' + y = 1
0 + 0 + c = 1
c = 1
So the total solution is:
y(t) = c₁ e^(-1/2 t) cos(√3/2 t) + c₂ e^(-1/2 t) sin(√3/2 t) + 1
To solve for c₁ and c₂, you need to be given initial conditions.
Answer:
( x - 3 )( x + 3 ) ( x - 4 )( x + 4)
Step-by-step explanation:
( x^2 - 9 ) ( x^2 - 16 )
( x - 3 )( x + 3 ) ( x - 4 )( x + 4)
Hopefully this helps!
Brainliest please?
Answer:
C. 5 is solution of the inequality: B>2.1
Answer:
(3x + 4)(2x - 5)
<em> = (3x + 4)(2x - 5)</em>
Hope this helped! Have a great day!
