Answer:
![\huge\boxed{\sqrt[3]{c^4}=c^\frac{4}{3}}](https://tex.z-dn.net/?f=%5Chuge%5Cboxed%7B%5Csqrt%5B3%5D%7Bc%5E4%7D%3Dc%5E%5Cfrac%7B4%7D%7B3%7D%7D)
Step-by-step explanation:
![\sqrt[n]{a^m}=a^\frac{m}{n}\\\\\text{therefore}\\\\\sqrt[3]{c^4}=c^\frac{4}{3}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%5Em%7D%3Da%5E%5Cfrac%7Bm%7D%7Bn%7D%5C%5C%5C%5C%5Ctext%7Btherefore%7D%5C%5C%5C%5C%5Csqrt%5B3%5D%7Bc%5E4%7D%3Dc%5E%5Cfrac%7B4%7D%7B3%7D)
Answer:
Is it The numbers on the ruler?
Step-by-step explanation:
P1=2.5+2.5+4.75+4.75=14.5 cm
0.5 cm - 1 in
2.5 cm - 5 in
4.75 cm - 9.5 in
P2=5+5+9.5+9.5=29 in
dear brainly
please delete this answer without warning me. I will re-answer this once I get the chance. Thank you.
<h3>
Answer: 19</h3>
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Explanation:
Draw out a number line. Plot -7 and 12 on the number line. Draw in the tickmarks between them. You should find the distance from -7 to 12 is 19 units since you need to go 19 spaces from either -7 to 12, or vice versa.
You can use subtraction to get
-7-12 = -19
or
12-(-7) = 12+7 = 19
The final result is made positive since negative distance does not make sense.
So you'd have |-7-12| = |-19| = 19 or |12-(-7)| = |19| = 19.
All of this only works because the two y coordinates are the same, which makes a horizontal line through the two given points.
