I believe it to be 1 over 3 as 1 as the numerator and 3 as the denominator
Answer:
The given sequence 6, 7, 13, 20, ... is a recursive sequence
Step-by-step explanation:
As the given sequence is
- It cannot be an arithmetic sequence as the common difference between two consecutive terms in not constant.
As
,
As d is not same. Hence, it cannot be an arithmetic sequence.
- It also cannot be a geometrical sequence and exponential sequence.
It cannot be geometric sequence as the common ratio between two consecutive terms in not constant.
As
,
,
As r is not same, Hence, it cannot be a geometric sequence or exponential sequence. As exponential sequence and geometric sequence are basically the same thing.
So, if we carefully observe, we can determine that:
- The given sequence 6, 7, 13, 20, ... is a recursive sequence.
Please have a close look that each term is being created by adding the preceding two terms.
For example, the sequence is generated by starting from 1.
and
for n > 1.
<em>Keywords: sequence, arithmetic sequence, geometric sequence, exponential sequence</em>
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Each person gets 1 1/4 bars.
You divide the 5 bars by 4 people: 5/4 = 1 1/4
Answer:
A
Step-by-step explanation:
The equation of a circle in standard form is
(x - h)² + (y - k)² = r²
where (h, k) are the coordinates of the centre and r is the radius
Given (h, k) = (0, - 7) and r = 11, then
(x - 0)² + (y - (- 7))² = 11², that is
x² + (y + 7)² = 121 → A