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seropon [69]
4 years ago
8

Use the information about budgets on page 352 to explain how inequalities are used in finances. Include an explanation of the re

strictions placed on the domain and range of the inequality that describes the number of times Hannah can buy lunch. Describe three possible solutions of the inequality. ( Info ) Hannah budgets $30 a month for lunch. On most days, she brings her lunch. She can also buy lunch at the cafeteria or at a fast-food restaurant. She spends an average of $3 for lunch at the cafeteria and an average of $4 for lunch at a restaurant. How many times a month can Hannah buy her lunch and remain within her budget? The cost of eating in the cafeteria plus the cost of eating in a restaurant is less than or equal to$30. Let x = the number of days she buys lunch at the cafeteria.Let y = the number of days she buys lunch at a restaurant 3x +4y ≤30 There are many solutions for this inequality. Each solution represents a different combination of lunches bought in the cafeteria and in a restaurant.
Mathematics
1 answer:
mrs_skeptik [129]4 years ago
7 0
*it by 15 and you will get the answer
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Answer:

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Step-by-step explanation:

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The acceleration, in meters per second per second, of a race car is modeled by A(t)=t^3−15/2t^2+12t+10, where t is measured in s
oksian1 [2.3K]

Answer:

The maximum acceleration over that interval is A(6) = 28.

Step-by-step explanation:

The acceleration of this car is modelled as a function of the variable t.

Notice that the interval of interest 0 \le t \le 6 is closed on both ends. In other words, this interval includes both endpoints: t = 0 and t= 6. Over this interval, the value of A(t) might be maximized when t is at the following:

  • One of the two endpoints of this interval, where t = 0 or t = 6.
  • A local maximum of A(t), where A^\prime(t) = 0 (first derivative of A(t)\! is zero) and A^{\prime\prime}(t) (second derivative of \! A(t) is smaller than zero.)

Start by calculating the value of A(t) at the two endpoints:

  • A(0) = 10.
  • A(6) = 28.

Apply the power rule to find the first and second derivatives of A(t):

\begin{aligned} A^{\prime}(t) &= 3\, t^{2} - 15\, t + 12 \\ &= 3\, (t - 1) \, (t + 4)\end{aligned}.

\displaystyle A^{\prime\prime}(t) = 6\, t - 15.

Notice that both t = 1 and t = 4 are first derivatives of A^{\prime}(t) over the interval 0 \le t \le 6.

However, among these two zeros, only t = 1\! ensures that the second derivative A^{\prime\prime}(t) is smaller than zero (that is: A^{\prime\prime}(1) < 0.) If the second derivative A^{\prime\prime}(t)\! is non-negative, that zero of A^{\prime}(t) would either be an inflection point (ifA^{\prime\prime}(t) = 0) or a local minimum (if A^{\prime\prime}(t) > 0.)

Therefore \! t = 1 would be the only local maximum over the interval 0 \le t \le 6\!.

Calculate the value of A(t) at this local maximum:

  • A(1) = 15.5.

Compare these three possible maximum values of A(t) over the interval 0 \le t \le 6. Apparently, t = 6 would maximize the value of A(t)\!. That is: A(6) = 28 gives the maximum value of \! A(t) over the interval 0 \le t \le 6\!.

However, note that the maximum over this interval exists because t = 6\! is indeed part of the 0 \le t \le 6 interval. For example, the same A(t) would have no maximum over the interval 0 \le t < 6 (which does not include t = 6.)

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3 years ago
A regression analysis between weight (y in pounds) and height (x in inches) resulted in the following least squares line: ŷ = 13
Lunna [17]

Answer:

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And for this case the interpretation for the slope would be that for every unit that the height in inches increase then the weight in pounds increase 6 units.

For the intercept of 135 represent the amount initial amount of weight for the scale.

Step-by-step explanation:

We assume that they use least squares in order to create the regression equation

For this case we need to calculate the slope with the following formula:

m=\frac{S_{xy}}{S_{xx}}

Where:

S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}

S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}

With these we can find the sums:

And the slope would be:

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The means for x and y are given by:

\bar x= \frac{\sum x_i}{n}

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And we can find the intercept using this:

b=\bar y -m \bar x

For this case we know that the line adjusted is:

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And for this case the interpretation for the slope would be that for every unit that the height in inches increase then the weight in pounds increase 6 units.

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Answer:

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Step-by-step explanation:

hope it help

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