Let's define variables:
s = original speed
s + 12 = faster speed
The time for the half of the route is:
60 / s
The time for the second half of the route is:
60 / (s + 12)
The equation for the time of the trip is:
60 / s + 60 / (s + 12) + 1/6 = 120 / s
Where,
1/6: held up for 10 minutes (in hours).
Rewriting the equation we have:
6s (60) + s (s + 12) = 60 * 6 (s + 12)
360s + s ^ 2 + 12s = 360s + 4320
s ^ 2 + 12s = 4320
s ^ 2 + 12s - 4320 = 0
We factor the equation:
(s + 72) (s-60) = 0
We take the positive root so that the problem makes physical sense.
s = 60 Km / h
Answer:
The original speed of the train before it was held up is:
s = 60 Km / h
<em>Answer: 42 + 18b</em>
<em>Hello!</em>
<em>____________________-</em>
<em>6(7 + 3b) = </em>
<em>42 + 18b</em>
<em>Step-by-step explanation: Simplify the expression.</em>
<em>Hope this helped you!</em>
<em></em>
Answer:
x = 2
Step-by-step explanation:
Given the 2 equations
2x + y = 3 → (1)
5x - 2y = 12 → (2)
Multiplying (1) by 2 and adding to (2) will eliminate the y- term
4x + 2y = 6 → (3)
Add (2) and (3) term by term
(5x + 4x ) +( - 2y + 2y) = 12 + 6 , that is
9x = 18 ( divide both sides by 9 )
x = 2
Answer: This question is confusing because I can't come up with a whole answer because I don't see a way to get to it no matter how many different ways I try to solve it ;-; The closest I got was $267 with 10 tickets and the fee
Step-by-step explanation:
Remove unnecessary parenthesis, and combine like terms
(3+i) + (5-2i)
3+i + 5-2i
8+i
you added 3+5 which is 5 and i-2i which is "i"
hope this helps.
