Equation of a circle in standard form:
(x-h)²+(y-k)²=r²
r=radius
(h,k) is the center.
In this case:
(h,k) =(0,0) (h=0,k=0 )
r=4
Therefore:
(x-0)²+(y-0)²=4²
x²+y²=16
Answer: x²+y²=16
Answer:
<u>The domain is the set of x-values:</u>
<u>The range is the set of y-values:</u>
This can be a function as each x- value has exactly one corresponding y- value.
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Answer:
3m^2
Step-by-step explanation:
i hope this helps!! :)
