Answer: 40
Step-by-step explanation: I’m not too sure but 1,080 divided by 27 equals 40
Answer:
(a) ![0.408m/sec^2](https://tex.z-dn.net/?f=0.408m%2Fsec%5E2)
(b) ![0.134m/sec^2](https://tex.z-dn.net/?f=0.134m%2Fsec%5E2)
(c) ![0.039m/sec^2](https://tex.z-dn.net/?f=0.039m%2Fsec%5E2)
Step-by-step explanation:
We have given velocity as function of t ![v(t)=\frac{85t}{(8t+14)}](https://tex.z-dn.net/?f=v%28t%29%3D%5Cfrac%7B85t%7D%7B%288t%2B14%29%7D)
Acceleration is equation rate if change of velocity with respect to time
So ![a=\frac{dv}{dt}=\frac{(8t+14)85-85t\times 8}{(8t+14)^2}](https://tex.z-dn.net/?f=a%3D%5Cfrac%7Bdv%7D%7Bdt%7D%3D%5Cfrac%7B%288t%2B14%2985-85t%5Ctimes%208%7D%7B%288t%2B14%29%5E2%7D)
(a) Acceleration at t = 5 sec
![a=\frac{(8\times 5+14)85-85\times 5\times 8}{(8\times 5+14)^2}=0.408m/sec^2](https://tex.z-dn.net/?f=a%3D%5Cfrac%7B%288%5Ctimes%205%2B14%2985-85%5Ctimes%205%5Ctimes%208%7D%7B%288%5Ctimes%205%2B14%29%5E2%7D%3D0.408m%2Fsec%5E2)
(b) Acceleration at t = 10 sec
![a=\frac{(8\times 10+14)85-85\times 10\times 8}{(8\times 10+14)^2}=0.134m/sec^2](https://tex.z-dn.net/?f=a%3D%5Cfrac%7B%288%5Ctimes%2010%2B14%2985-85%5Ctimes%2010%5Ctimes%208%7D%7B%288%5Ctimes%2010%2B14%29%5E2%7D%3D0.134m%2Fsec%5E2)
(c) Acceleration at t = 20 sec
![a=\frac{(8\times 20+14)85-85\times 20\times 8}{(8\times 20+14)^2}=0.039m/sec^2](https://tex.z-dn.net/?f=a%3D%5Cfrac%7B%288%5Ctimes%2020%2B14%2985-85%5Ctimes%2020%5Ctimes%208%7D%7B%288%5Ctimes%2020%2B14%29%5E2%7D%3D0.039m%2Fsec%5E2)
Answer:
Step-by-step explanation:
if the volume is V=s^3
Winston has to do
V=0.5^3=0.125 cm^3
Take the fouth square root of both sides
![\sqrt[4]{{x}^{4} } = \sqrt[4]{24}](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B%7Bx%7D%5E%7B4%7D%20%7D%20%20%3D%20%20%5Csqrt%5B4%5D%7B24%7D%20)
so