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3 years ago

a mail truck travels 82 miles in 412 hours. to the nearest tenth, what was the average speed of the mail truck?

1 answer:

8 0

The question is asking to calculate the average speed of the mail truck if it travels 82 miles in just 412 hours, base on that, the possible answer would be that the average speed of the truck is 0.2 miles per hour. I hope you are satisfied with my answer and feel free to ask for more

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PLEASEEEE !!!!!! Help me figure out the length centimeters of LM. And the largest angle and measure !! WILL MARK BRIANLIEST !!!!

zmey [24]

Answer:

we really can't tell because we are not able to use a protactor and a ruler

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3 years ago

Please help, Find the perimeter of the figure to the nearest hundredth

ElenaW [278]

Answer:

36.56 in

Step-by-step explanation:

perimeter is the sum of all sides

u add all the sides of the square by 6

6+ 6 + 6 + 6 = 24

circumference is the line around the circle

circumference = 3.14 x diameter

c = 3.14 x 4

c = 12.56

24 + 12.56 = 36.56

to the NEAREST HUNDREDTH????? ok welll thats alr

remember

5 or more, raise the score

4 or less, let it rest

this should be fine since the last 6 is alr in the hundredth place :)

like this up !!

6 0

3 years ago

Read 2 more answers

Four plants orbit a star at the following distances.Which one is the closes to the star?

vredina [299]

Answer: Easily A.

Step-by-step explanation: All you have to do is look at the power of the tens. The one that is the least is A. Since none of the other choices are equal to or less than 10^7, A is your answer. In scientific notation, you almost always look at the 10^x first.

5 0

3 years ago

Write in standard notation (1/sqrt2-1/sqrt2 i)^6

vesna_86 [32]

Hello,

z=(1/√2-1/√2 i)^6=1/8*(1-i)^6=1/8*(√2∡-45°)^6=1/8*8∡-270°=1∡90°=i
======================================================

7 0

3 years ago

What are the coordinates of the orthocenter of △JKL with vertices at J(−4, −1) , K(−4, 8) , and L(2, 8) ?

Sati [7]

Answer-

The coordinates of the orthocenter of △JKL is (-4, 8)

Solution-

The orthocenter is the point where all three altitudes of the triangle intersect. An altitude is a line which passes through a vertex of the triangle and is perpendicular to the opposite side.

For a right angle triangle, the vertex at the right angle is the orthocentre of the triangle.

Here we are given the three vertices of the triangle are J(-4,-1), K(-4,8) and L(2,8)

If the triangle JKL satisfies Pythagoras Theorem, then triangle JKL will be a right angle triangle.

Applying distance formula we get,

$JK^2= (-4+4)^2+ (8+1)^2=0+81=81\\\\KL^2= (-4-2)^2+ (8-8)^2=36+0=36\\\\JL^2= (-4-2)^2+(8+1)^2=36+81=117$

As,

$\Rightarrow 117=81+36$

$\Rightarrow JL^2=JK^2+KL^2$

$\Rightarrow \text{JKL is a right angle triangle}$

$\Rightarrow \angle K=90^{\circ}$

Therefore, the vertex at K (-4, 8) is the orthocentre.

3 0

3 years ago