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DanielleElmas [232]
3 years ago
9

Mr. Luu spent 15.99 on new flashlights. If 12 students are using flashlights what is the unit cost per student round the answer

to the nearest hundreds.
Mathematics
1 answer:
Nataliya [291]3 years ago
8 0

Answer:

$1.33 per student

Step-by-step explanation:

Mr. Luu spent 15.99 on new flashlights.

Total number of students = 12

We need to find the unit cost per student. It can be calculated by dividing the total cost and the total number of students.

C=\dfrac{15.99}{12}\\\\C=1.33

So, the required cost per student is 1.33.

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So she divided the 2/3 between 4 friends.

So each friend got 2/3 divided by 4, which gives:

(2/3)*(1/4) = 2/12 = 1/6
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3 years ago
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a) x^3y2

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2 years ago
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A solution initially contains 200 bacteria. 1. Assuming the number y increases at a rate proportional to the number present, wri
GuDViN [60]

Answer:

1.\frac{dy}{dt}=ky

2.543.6

Step-by-step explanation:

We are given that

y(0)=200

Let y be the number of bacteria at any time

\frac{dy}{dt}=Number of bacteria per unit time

\frac{dy}{dt}\proportional y

\frac{dy}{dt}=ky

Where k=Proportionality constant

2.\frac{dy}{y}=kdt,y'(0)=100

Integrating on both sides then, we get

lny=kt+C

We have y(0)=200

Substitute the values then , we get

ln 200=k(0)+C

C=ln 200

Substitute the value of C then we get

ln y=kt+ln 200

ln y-ln200=kt

ln\frac{y}{200}=kt

\frac{y}{200}=e^{kt}

y=200e^{kt}

Differentiate w.r.t

y'=200ke^{kt}

Substitute the given condition then, we get

100=200ke^{0}=200 \;because \;e^0=1

k=\frac{100}{200}=\frac{1}{2}

y=200e^{\frac{t}{2}}

Substitute t=2

Then, we get y=200e^{\frac{2}{2}}=200e

y=200(2.718)=543.6=543.6

e=2.718

Hence, the number of bacteria after 2 hours=543.6

4 0
4 years ago
Can you solve 35÷5+56÷7
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Order of operations

first divide, than add

35/5 = 7
56/7 = 8

7 + 8 = 15

15 is your answer

hope this helps
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4 years ago
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