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serious [3.7K]
3 years ago
5

PLEASE HELP! BIG POINTS!!!!;)

Mathematics
2 answers:
inysia [295]3 years ago
5 0

Answer:

2.5

Step-by-step explanation:

ok so triangle RST is half the size of triangle XYZ

cuz RT equals 8 and XY equals 16 meaning their half the size (8 x 2 = 16)

so all we have to do is divide 5 by half : 5/2 = 2.5

~batmans wife dun dun dun.....

KengaRu [80]3 years ago
4 0
The value of b would be 2.5.

As you can see on the picture, the hypotenuse side goes from 8 to 16. Therefore, we know that b has to be half of 5. 

I hope this helped you.

Brainliest answer is always appreciated. <span />
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There are 4 white marbles but there are 27 marbles in total. If you wanted a percentage, then divide 4 by 27 and place the decimal two places to the right once you founded your answer.

(sorry if it's a bad explanation)

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Solving Linear equations 25 =x + 19
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3 years ago
If α and β are the zeros of the quadratic polynomial f(x) = 3x2–4x + 5, find a polynomialwhose zeros are 2α + 3β and 3α + 2β.
Lelechka [254]

Answer:

\boxed{\sf \ \ \ 3x^2-20x+37\ \ \ }

Step-by-step explanation:

Hello,

a and b are the zeros, we can say that

f(x)=3(x^2-\dfrac{4}{3}x+\dfrac{5}{3}) = 3(x-a)(x-b)=3(x-(a+b)x+ab)

So we can say that

a+b=\dfrac{4}{3}\\ab=\dfrac{5}{3}

Now, we are looking for a polynomial where zeros are 2a+3b and 3a+2b

for instance we can write

(x-2a-3b)(x-3a-2b)=x^2-(2a+3b+3a+2b)x+(2a+3b)(3a+2b)\\= x^2-5(a+b)x+6a^2+6b^2+9ab+4ab

and we can notice that

a^2+b^2=(a+b)^2-2ab so

(x-2a-3b)(x-3a-2b)=x^2-5(a+b)x+6[(a+b)2-2ab]+13ab\\= x^2-5(a+b)x+6(a+b)^2+ab

it comes

x^2-5*\dfrac{4}{3}x+6(\dfrac{4}{3})^2+\dfrac{5}{3}

multiply by 3

3x^2-20x+2*16+5=3x^2-20x+37

4 0
3 years ago
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